Proof that the Area of a Triangle = bh/2

1 / (1 + x)3 = 1 – 3x + 6x2 – 10x3 + 15x4 – … Sqrt(1 – x) = 1 – (1/2)x – (1/8)x2 – (1/16)x3 – (5/128)x4 – … So, sqrt(7) = 3 sqrt(1 – 2/9) ( fast approximation for square roots! Also cube roots, etc, since (1 – x)1/3 can be expanded this way, too… Summer Math Series: Week 5 Newton’s Calculus ................
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