Double integrals

1 0 " 3y −xy − y2 2 # y=x y=0 dx = Z 1 0 3x−x2 − x2 2! dx = Z 1 0 3x− 3x2 2! dx = " 3x2 2 − x3 2 # 1 x=0 = 1 Note that Methods 1 and 2 give the same answer. If they don’t it means something is wrong. 0.11 Example Evaluate ZZ D (4x+2)dA where D is the region enclosed by the curves y = x2 and y = 2x. Solution. Again we will carry ... ................
................