Calculus II, Section 7.6, #46 Integration Using Tables and ...

Integrate[(1+Log[x])*Sqrt[1+(x*Log[x])^2],x] and we get So WjA is unable to evaluate the integral. Let u = 1 + (xln(x))2, then du = 2(xln(x)) x1 x +ln(x)1 = 2(xln(x))(1+ln(x))dx. This is not a good result for us|the factor 2(xln(x)) is not present in the integrand|but this does show us that the derivative of xln(x) is present in the integrand ... ................
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