NATIONAL SENIOR CERTIFICATE GRADE 12 MATHEMATICAL LITERACY P1 ...
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NATIONAL SENIOR CERTIFICATE
GRADE 12
MATHEMATICAL LITERACY P1 PREPARATORY EXAMINATION
MARKING GUIDELINE SEPTEMBER 2019
MARKS: 150
SYMBOL
M MA CA A C
S RT/RG/RD/RM
SF O J R F AO P NPR
EXPLANATION
Method Method with accuracy Consistent accuracy Accuracy Conversion Simplification Reading from a table/ graph/ diagram/map Correct substitution in a formula Opinion/ reason/deduction/example/Explanation Justification Rounding off deriving a formula Answer only full marks Penalty e.g. for units, incorrect rounding off etc. No penalty for rounding / units
This marking guideline consists of 12 pages.
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Mathematical Literacy/P1
2 Prep Exam - Marking Guideline
KZN/September 2019
QUESTION 1 [33 MARKS]
Ques. No
Solution
1.1.1 Cost price = R38,00 MA 50
= R0,76 A OR 76c
1.1.2 Profit = R1,10 ? R0,76 M = R0,34 CA OR 34c
1.1.3 Cost price = R38,00 ? 12 M = R456,00 CA OR
Cost price = 600 ? 76c M = 45 600 c CA
1.2.1 20 litres ? 1 000 C = 20 000 ml A
1.2.2
glass capacity: bucket capacity 200 ml : 20 ? 1 000 S 200 : 20 000 MA 1 : 100 CA
OR 200 C 1000
0,2 : 20 MA
1 : 100 CA
1.2.3 Number of people = 100 A
Explanation 1MA dividing by 50
T&L
F L1
1A cost price AO
1M subtraction 1CA profit AO
1M multiplying by 12 1CA cost price
(2) F L1
(2) F L1
OR
1M multiplying 600 by 76c
1CA cost price AO
1C conversion
(2) F L1
1A number of ml AO
1S simplification 1MA correct order 1CA ratio
OR 1C conversion
(2) M L1
(3)
1MA correct order
1CA ratio AO 2A number of people AO
M L1 (2)
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KZN/September 2019
Ques. No
1.3.1
Solution Number of CDs = 5 +10+3+7+3 MA
= 28 A
1.3.2 Outcome means a possible result after an event or events. O
1.3.3 P (jazz CD) = 0% A
Explanation
1MA addition 1A number of CDs AO
T&L DH L1
(2)
2O
P
Accept any valid definition
L1
(2)
P
2A correct percentage
L1
1.4.1 Bar scale/Linear scale A Number scale/Ratio scale A
1.4.2 One unit on the map/paper represents nine million units in reality. E
1A bar scale/linear scale 1A number scale
2E explanation
(2) MP L1
(2)
MP (2) L1
1.5.1 Bidvest Wits RT
2RT name of club
1.5.2 Modal number of points = 29 RT
2RT modal number
1.5.3
Total matches = 21 +21 +19 + 20 +21 +21 +21 +20 + 21
+ 21 + 21 + 21 + 20 + 21 + 20 + 21 MA 1MA addition
= 330 CA
1CA total
DH (2) L1
DH (2) L1
DH L1
OR
OR
Total matches = 19 + (20 ? 4) + (21 ? 11) MA = 330 CA
1.5.4 Minimum = 14 A Maximum = 38 A
1MA addition and multiplication
1CA total AO
1A minimum 1A maximum
(2) DH L1
(2)
1.5.5 Mamelodi Sundowns RT
2RT reading from the table
DH
(2) L1
[33]
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4 Prep Exam - Marking Guideline
KZN/September 2019
QUESTION 2 [47 MARKS]
Ques. No
Solution
2.1.1
Sonia's budget for February 2019
Income
Expenses
Wages part time job
Rent R2 400,00 A
R2 250,00 A
Bursary allowance
Groceries
R1 950,00 A
R2 140,00A
Pocket money R1 500,00 A Transport R575,00A
Clothing store account
R455,00A
Total : R5 700,00 A
Total : R5 570,00 A
2.1.2 2.1.3
Surplus / Deficit = Income ? expenses = R5 700,00 ? R5 570,00 SF = R130,00 CA
transport: pocket money R 575 : R 1 500 A 23 : 60 S
2.2.1
Pace car rental
Total amount = (daily rate ? 4 days) + (number of km more than 800 km ? R2,42) + refundable deposit
= (R290 ? 4) + (2 800 km ? R2,42) + R10 000 SF
= R1 160 + R6 776 +R10 000 S
= R17 936,00 CA
Explanation
T&L
F L2
3A for income sources and amounts 4A for expenses and amounts 2A for totals
Accept other formats of budget
1SF correct substitution 1CA surplus
1A correct order 1A correct values 1S simplification
AO
(9) F L1
(2) F L1
(3)
F L2
1SF correct substitution 1S simplification 1CA amount
(3)
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No.
KZN/September 2019
Explanation
T & L
2.2.2 Flexi car rental
F
Total amount = (daily rate ? 4 days) + (number of km more
L2
than 600 km ? R2,82) + refundable deposit = (R326 ? 4) + (3 000km ? R2,82) +R10 000 SF
1SF correct substitution
= R1 304 + R8 460 + R10 000 S
1S simplification
= R19 764 CA
1CA amount
OR
OR
Total amount = (daily rate ? 4 days) + (number of km more than 600 km ? R2,83) + refundable deposit
= (R326 ? 4) + (3 000km ? R2,83) +R10 000 SF
= R1 304 + R8 490 + R10 000 S
1SF correct substitution 1S simplification 1CA amount
= R19 794 CA
(3)
2.2.3 Pace car rental is cheaper. CA
2CA opinion
F (2) L2
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Ques. No.
6 Prep Exam - Marking Guideline
Solution
2.3.1 Opening balance is the amount that is already in the account at the beginning of the month. E
OR
2.3.2
Opening balance is the amount carried forward from the previous month.
Opening balance = R1 855,52 RT
2.3.3 A = R1855,52 + R1500 MA O = R3 355,52 A
OR
A = R3005,02 + R350,50 MA = R3355,52 A
2.3.4
VAT exclusive amount = R100 M 1,14
= R87,71929825 A
R87,72 R
OR
VAT exclusive amount = R100 ? 100 M 114
= R87,71929825 A
R87,72 R
2.3.5 Credit O
KZN/September 2019
Explanation
T & L
F
2E explanation
L1
(2)
Accept any valid
definition
2RT opening balance F
NPR
L1
(2)
1MA adding correct F
values
L1
1A balance
OR
1MA adding correct
values
1A balance
NPR
(2)
F
1M dividing by 1,14 L2
1A amount 1R rounding
OR
1M dividing by 1,14
1A amount 1R rounding AO
(3)
2O opinion
F L1 (2)
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2.4.1
A
MA
Total cost = R650 + (R0,08 ? number of copies made)
OR
A
MA
Total cost = R650 + (8cents ? 100) ? number of copies made
KZN/September 2019
1A monthly charge
F
1MA
L2
multiply by R0,08
OR
1A monthly charge 1MA multiply by R0,08
2.4.2 2.4.3 2.4.4
A M Total cost = R0,30 ? number of copies made
OR A M Total cost = 30c x number of copies made A = R650 A
B = R0,30 ? 2 000 M
= R600 A
Cost in Rands
Graph showing number of copies made from GP and HP Printers
1400 1200 1000
800 A
600 400 200
0 0
A A
A
1000 2000 3000 4000 5000
Number of copies made
HP
Printer A
GP
Printer A
1A for R0,30 1M multiplication OR 1A for R0,30 1M multiplication
(2) F L2
(2)
2A monthly charge
F
1M multiplying by R0,30
L1
1A cost
AO
(4)
1A graph starting at R650
F
1A points correctly plotted HP L2
1A points correctly plotted GP
2A for both graphs' labels
1CA joining points
(6)
[47]
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8 Prep Exam - Marking Guideline
KZN/September 2019
QUESTION 3 [25 MARKS]
Ques.
Solution
No.
3.1.1 A ? semi circle/ half circle A
B ? rectangle A
3.1.2
Perimeter = (length + length) + (2 ? ? radius)
M
SF
A
= (105 m + 105m) + (2 ? 3,142 ? 27,5m)
= 210 m+ 172,81 m
= 382,81 m CA
OR
Explanation
T & L
2A semi/half circle 2A rectangle
1M adding two lengths 1A finding radius 1SF substitution 1CA perimeter
M L1
(4) M L2
OR
Perimeter = (length + length) + ( ? diameter)
M
SF
A
= (105 m + 105m) + (3,142 ? 55m)
= 210 m+ 172,81 m
= 382,81 m CA
3.1.3 Cost of fencing = 382,81 m ? R66,00 M = R25 265,46 CA
3.1.4
Area of a circle = ? radius2 M
= 3,142 ? (27,5m)2 SF = 2 376,1375 m2 CA
1M adding lengths
1A diameter
1SF substitution
1CA perimeter (4)
CA from 3.1.2
M
1M multiplying by R66,00 L1
1CA cost
(2)
1M radius
M
1 SF correct substitution
L2
1CA area
Area of a rectangle = length ? width = 105 m ? 55 m SF = 5 775 m2 CA
1 SF correct substitution 1CA area
Total area = 2 376,1375 m2 + 5 775 m2 M = 8 151,1375 m2 CA
8 151,14 m2 R
1M adding 1CA total area 1 R rounding
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