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Therefore the integral of Fdt is evaluated from t = 0 to t = v/a, and since s = (1/2)at2, the integral of Fds is evaluated from s = 0 to s = v2/(2a). Letting the symbol m (without subscript) denote the inertial mass of the particle given by the ratio p/v, if follows that the inertial mass and … ................
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