हिन्दी साहित्य- सीमांचल



|Refraction of Light |

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|Summary |

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|When a ray of light is incident on a boundary separating the two media having different densities: |

|A part of the light gets reflected. |

|Rest of the light changes its direction as it enters the second medium. |

|The change of direction suffered by a ray of light as it passes obliquely from one medium to another is known as refraction |

|Incident Ray |

|The ray of light striking the surface of separation of the media through which it is travelling is known as the incident ray. |

|Point of Incidence |

|The point at which the incident ray strikes the surface of separation is called the point of incidence. |

|Normal |

|The perpendicular drawn to the surface of separation at the point of incidence is called the normal. |

|Refracted Ray |

|The ray of light that has changed its direction at the surface of separation when travelling from one medium to another is called the |

|refracted ray. |

|Angle of Incidence |

|The angle, which the incident ray makes with the normal at the point of incidence, is called the angle of incidence. |

|Angle of Refraction |

|The angle, which the refracted ray makes with the normal at the point of incidence, is called the angle of refraction. |

|Laws of Refraction |

|The laws of refraction are: |

|The incident ray, the refracted ray and the normal to the surface at the point of incidence all lie in one plane. |

|For any two given pair of media, the ratio of the sine of the angle of incidence to the sine of the angle of refraction is a constant. |

|The second law is called Snell's law after the scientist Willebrod Snell who first formulated it |

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|where nm is the refractive index of the second medium with respect to the first medium. |

|Refractive Index |

|Refractive index or absolute refractive index of a medium is equal to the ratio of the speed of light in vacuum or air to the speed of |

|light in that particular medium. |

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|This ratio is always a constant for a given pair of media. |

|Lens |

|A lens is a transparent medium that has at least one curved surface. |

|Convex Lens |

|A convex lens is thicker in the middle and thinner at its edges. |

|Concave Lens |

|A concave lens is thicker at the edges and thinner in the middle. |

|Optic Centre |

|The centre of a lens is called the optical centre or optic centre. It is denoted by the letter O. |

|Centre of Curvature |

|The centres of the spherical surfaces forming a lens are known as the centres of curvature of the lens. The letter C is used to denote |

|centre of curvature. |

|Principal Axis |

|The line passing through the centres of curvature C1 and C2 of two spherical surfaces of the lens is called the principal axis of the |

|lens. |

|Principal Focus of a Convex Lens |

|The principal focus F of a convex lens is a point on the principal axis to which rays parallel to the principal axis converge after |

|refraction. |

|Principal Focus of a Concave Lens |

|The principal focus F of a concave lens is a point on the principal axis from which rays parallel to the principal axis appear to |

|diverge after refraction. |

|Focal Length |

|The distance between the optic centre and the focus is the focal length f of the lens. |

|Rays that are generally considered while constructing ray diagrams: |

|Any ray of light, travelling parallel to the principal axis, after refraction through the lens, passes through the principal focus of |

|the lens. |

|Any ray of light, which first passes through principal focus or which appears to meet at the focus after refraction, always travels |

|parallel to the principal axis. |

|Any ray of light which passes through optical centre of lens does not deviate form its path. |

|The image is formed at the point of intersection of these refracted rays. |

|Sign Convention for Lenses |

|All distances on the principal axis are measured from the optical centre. |

|The distances measured in the direction of incident rays are positive and all the distances measured in the direction opposite to that |

|of the incident rays are negative. |

|All distances measured perpendicular to and above the principal axis are positive. Thus, height of an object and that of an erect image |

|are positive |

|And all distances measured perpendicular to and below the principal axis are negative. |

|Lens Formula |

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|Where u is the object distance or distance of the object from the lens, v is the image distance or the distance of the image from the |

|lens and f is the focal length or the distance of the principal focus from the lens. |

|Magnification |

|It is the ratio of the height of the image to the height of the object. It is represented by the letter m |

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|Magnification produced by a lens is also related to the object distance u, and the image distance v. |

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|Power of a Lens |

|Power of a lens is defined as the reciprocal of its focal length in metres. |

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|The SI unit of power is dioptre |

|1D = 1 m-1 |

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|Question (1): The bending of a beam of light when it passes obliquely from one | |

|medium to another is known as _______. | |

| |Be an International Online Tutor |

|1. |Top of Form |

|reflection |Name |

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|2. | |

|refraction |Email |

| |[pic] |

|3. | |

|dispersion |Subject |

| |[pic] |

|4. | |

|deviation |Phone |

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|Ans:  2 |[pic][pic][pic][pic][pic] |

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| |Bottom of Form |

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|Question (2): The part of the lens through which the ray of light passes without |Get tutoring in Math, Algebra, Trigonometry, |

|suffering deviation is called ________. |Geometry, English, Physics, Chemistry and Biology |

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|1. |[pic] |

|optical centre | |

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|2. |Top Clicked |

|focus |tissues  gravitation  Valence Shell |

| |  isotopes  science questions  types of |

|3. |Respiration  photosynthesis  online math tutor |

|centre of curvature | |

| |Refraction of Light |

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|pole |Introduction |

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| |Refraction of Light |

|Ans:  1 | |

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| |Laws of Refraction |

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|Question (3): Convex lens always gives a real image if the object is situated |Refraction of Light through a Glass Slab |

|beyond _______. | |

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|1. |Verification of Laws of Refraction - An Alternate |

|optical centre |Method |

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|2. |• |

|centre of curvature |Lenses |

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|3. |• |

|focus |Terminology Used in Optics |

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|4. |• |

|radius of curvature |Formation of Image by a Convex Lens |

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| |Formation of Image by a Concave Lens |

|Ans: 3 | |

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| |Sign Convention for Lenses |

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|Question (4): Parallel rays of light entering a convex lens always converge at |Lens Formula |

|_______. | |

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|1. |Magnification |

|centre of curvature | |

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|2. |Power of a Lens |

|the principal focus | |

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|3. |Summary |

|optical centre | |

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|4. |Question and Answers |

|the focal plane | |

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| |Multiple Choice Questions |

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|Ans:  2 | |

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|Question (5): Where should an object be placed so that a real and inverted image | |

|of the same size is obtained, using a convex lens? | |

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|1. | |

|Between O and F | |

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|2. | |

|At F | |

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|3. | |

|At 2 F | |

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|4. | |

|At infinity | |

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|Ans:  3 | |

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|Question (6): SI unit of the power of a lens is ___________. | |

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|1. | |

|dioptre | |

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|2. | |

|cm | |

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|3. | |

|metre | |

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|4. | |

|watt | |

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|Ans:  1 | |

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|Question (7): 1 D is the power of the lens of focal length of ______ cm. | |

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|1. | |

|100 | |

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|2. | |

|10 | |

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|3. | |

|1/100 | |

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|4. | |

|1/10 | |

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|Ans:  1 | |

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|Question (8): In a simple microscope lens used is __________. | |

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|1. | |

|biconvex | |

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|2. | |

|biconcave | |

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|3. | |

|plano convex | |

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|4. | |

|cylindrical | |

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|Ans:  1 | |

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|Question (9): Reciprocal of focal length in metres is known as the ______ of a | |

|lens. | |

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|1. | |

|focus | |

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|2. | |

|power | |

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|3. | |

|power of accommodation | |

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|4. | |

|far point | |

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|Ans:  2 | |

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|Question (10): A convex lens is called _________. | |

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|1. | |

|converging lens | |

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|2. | |

|diverging lens | |

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|3. | |

|both converging and diverging lens | |

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|4. | |

|refracting lens | |

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|Ans:  1 | |

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|Question (11): A positive magnification greater than unity indicates | |

|_____________________. | |

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|1. | |

|real image | |

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|2. | |

|virtual image | |

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|3. | |

|neither real not virtual image | |

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|4. | |

|distorted image | |

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|Ans:  2 | |

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|Question (12): The power of a convex lens of focal length 50 cm is ______. | |

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|1. | |

|+ 2D | |

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|2. | |

|- 2D | |

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|3. | |

|50 D | |

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|4. | |

|- 5D | |

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|Ans:  1 | |

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|Question (13): The focal length of a lens whose power is -1.5 D is _______. | |

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|1. | |

|-66.66 cm | |

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|2. | |

|+ 1.5 m | |

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|3. | |

|+ 66.66 cm | |

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|4. | |

|-1.5 m | |

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|Ans:  1 | |

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|Question (14): Real images formed by single convex lenses are always | |

|________________. | |

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|1. | |

|on the same side of the lens as the object | |

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|2. | |

|inverted | |

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|3. | |

|erect | |

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|4. | |

|smaller than the object | |

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|Ans:  2 | |

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|Question (15): An object is placed 12 cm from a convex lens whose focal length is | |

|10 cm. The image must be. | |

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|1. | |

|virtual and enlarged | |

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|2. | |

|virtual and reduced in size | |

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|3. | |

|real and reduced in size | |

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|4. | |

|real and enlarged | |

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|Ans:  4 | |

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|Question (16): When a person uses a convex lens as a simple magnifying glass, the | |

|object must be placed at a distance. | |

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|1. | |

|less than one focal length | |

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|2. | |

|more than one focal length | |

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|3. | |

|less than twice the focal length | |

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|4. | |

|more than twice the focal length | |

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|Ans:  1 | |

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|Question (17): The image produced by a concave lens is ________. | |

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|1. | |

|always virtual and enlarged | |

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|2. | |

|always virtual and reduced in size | |

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|3. | |

|always real | |

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|4. | |

|sometimes real, sometimes virtual | |

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|Ans:  2 | |

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|Question (18): A virtual image is formed by _______. | |

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|1. | |

|a slide projector in a cinema hall | |

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|2. | |

|the ordinary camera | |

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|3. | |

|a simple microscope | |

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|4. | |

|telescope | |

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|Ans:  3 | |

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|Question (19): An object is placed 25 cm from a convex lens whose focal length is | |

|10 cm. The image distance is ________ cm. | |

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|50 cm | |

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|2. | |

|16.66 cm | |

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|3. | |

|6.66 cm | |

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|4. | |

|10 cm | |

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|Ans:  2 | |

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|Question (20): The least distance of distinct vision is ______. | |

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|1. | |

|25 cm | |

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|2. | |

|25 m | |

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|3. | |

|0.25 cm | |

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|4. | |

|2.5 m | |

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|Ans:  1 | |

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|Question (21): A convex lens has a focal length of 20 cm. Its power in dioptres is| |

|___________. | |

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|1. | |

|2 | |

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|2. | |

|5 | |

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|3. | |

|0.5 | |

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|4. | |

|0.2 | |

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|Ans:  2 | |

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|Question (22): An object is placed before a concave lens. The image formed | |

|_____________-. | |

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|1. | |

|is always erect | |

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|2. | |

|may be erect or inverted | |

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|3. | |

|is always inverted | |

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|4. | |

|is always real | |

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|Ans:  1 | |

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|Question (23): A ray of light travels from a medium of refractive index n1 to a | |

|medium of refractive index n2. If angle of incidence is i and the angle of | |

|refraction is r. | |

|Then [pic]is equal to | |

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|1. | |

|n1 | |

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|2. | |

|n2 | |

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|3. | |

|n21 | |

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|4. | |

|n12 | |

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|Ans:  3 | |

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|Question (24): Two thin lenses of power +5 D and -2 D are placed in contact with | |

|each other. Focal length of the combination is | |

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|1. | |

|+3 m | |

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|2. | |

|-3 m | |

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|3. | |

|0.33 m | |

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|4. | |

|-0.33 m | |

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|Ans:  3 | |

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|Question (25): The lens formula in cartesian frame is ______________. | |

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|1. | |

|[pic] | |

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|2. | |

|[pic] | |

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|3. | |

|[pic] | |

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|4. | |

|[pic] | |

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|Ans: 3 | |

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|Question (1): Define refraction. | |

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|Answer:  The deviation in the path of light when it passes from one medium to another medium of |Be an International Online Tutor |

|different density is called refraction. |Top of Form |

| |Name |

| |[pic] |

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| |Email |

|Question (2): Define refractive index. |[pic] |

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|Answer:  The ratio of the speed of light in vacuum to the speed of light in a medium is called |Subject |

|the refractive index of the medium. |[pic] |

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| |Phone |

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|Question (3): What is the unit of refractive index? |  |

| |[pic][pic][pic][pic][pic] |

|Answer:  Refractive index is the ratio of velocity of light in two media and hence it is a mere | |

|number without any unit. |Bottom of Form |

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| |Get tutoring in Math, Algebra, |

| |Trigonometry, Geometry, English, |

|Question (4): List out the factors on which the refractive index of a medium depends. |Physics, Chemistry and Biology |

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|Answer:  The refractive index of a medium depends on |[pic] |

|1) the nature of the medium | |

|2) the colour or wavelength of the incident light | |

| |Top Clicked |

| |tissues  gravitation  Valence Shell |

| |  isotopes  science questions  types|

| |of |

|Question (5): Define angle of incidence. |Respiration  photosynthesis  online |

| |math tutor |

|Answer:  The angle which the incident ray makes with the normal at the point of incidence is | |

|called the angle of incidence. |Refraction of Light |

| |• |

| |Introduction |

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|Question (6): What is the angle of incidence if a ray of light is incident normal to the surface |Refraction of Light |

|separating the two media? | |

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|Answer:  Angle of incidence is equal to zero if a ray of light is incident normal to the surface |Laws of Refraction |

|separating the two media. | |

| |• |

| |Refraction of Light through a Glass |

| |Slab |

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|Question (7): What is a lens? |• |

| |Verification of Laws of Refraction -|

|Answer:  A lens is a portion of a transparent refracting medium bounded by two spherical surfaces|An Alternate Method |

|which are generally spherical or cylindrical or one curved and one plane surface. | |

| |• |

| |Lenses |

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|Question (8): What is a concave lens? |Terminology Used in Optics |

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|Answer:  A lens which is thinner at the middle and thicker at the edges is called a concave lens.|• |

| |Formation of Image by a Convex Lens |

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| |• |

| |Formation of Image by a Concave Lens|

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|Question (9): What is the nature of the focus of a concave lens? | |

| |• |

|Answer:  The focus of a concave lens is virtual. |Sign Convention for Lenses |

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| |• |

| |Lens Formula |

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|Question (10): What type of image is formed by a concave lens? |• |

| |Magnification |

|Answer:  A concave lens always forms a virtual and erect image. | |

| |• |

| |Power of a Lens |

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|Question (11): A thin lens has a focal length f = -12 cm. Is it convex or concave lens? |Summary |

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|Answer:  The lens is concave since the focal length is negative. |• |

| |Question and Answers |

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| |• |

| |Multiple Choice Questions |

|Question (12): A lens forms an erect image for all positions of the object in front of it. Is the| |

|lens convex or concave? | |

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|Answer:  Concave lens. | |

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|Question (13): Where should an object be placed so that a real and inverted image of same size is| |

|obtained using a convex lens? | |

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|Answer:  The object has to be placed at 2F to get a real and inverted image of same size. | |

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|Question (14): Write the relation between u,v and f of a thin lens. | |

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|Answer:  | |

|[pic] | |

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|Question (15): What is the sign of u, v and f for a convex lens according to Cartesian sign | |

|convention? | |

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|Answer:  According to sign convention u is negative, v is positive for all positions of the | |

|object except when the object is between the optic centre and first focus and f is positive. | |

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|Question (16): An object of height 1m is placed at a distance of 2f from a convex lens. What is | |

|the height of the image formed? | |

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|Answer:  The height will also be equal to 1m since the object placed at 2F of a convex lens gives| |

|an image of the same at 2F on the other side of the lens. | |

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|Question (17): Define power. | |

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|Answer:  The power of a lens is defined as the reciprocal of its focal length in metres. | |

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|Question (18): What is least distance of distinct vision? | |

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|Answer:  The minimum distance upto which an eye can see clearly is called the least distance of | |

|distinct vision. | |

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|Question (19): What happens when a ray of light passes through the optical centre of a lens? | |

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|Answer:  The ray of light does not suffer any deviation. | |

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|Question (20): State the laws of refraction. | |

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|Answer:  | |

|1) The incident ray, the refracted ray and the normal at the point of incidence all lie in one | |

|plane. | |

|2) For any two given pair of media, the ratio of the sine of the angle of incidence to the sine | |

|of the angle of refraction is a constant. | |

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|Question (21): Diagrammatically represent the refraction of light through a rectangular glass | |

|slab. | |

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|Answer:  | |

|[pic] | |

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|Question (22): Define convex lens. Why is it referred to as converging lens? | |

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|Answer:  A lens which is thicker in the middle and thinner at the edges is called convex lens. | |

|Convex lens is referred to as a converging lens because the parallel rays of light after | |

|refraction through a convex lens meet at a point on the principal axis. | |

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|Question (23): Draw a diagram to show the second principal focus of a convex lens. | |

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|Answer:  | |

|[pic] | |

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|Question (24): Distinguish between a convex and a concave lens. | |

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|Answer:  | |

|Convex lens | |

|Concave lens | |

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|Is thicker in the middle and thinner at the edges | |

|Is thinner at the middle and thicker at the edges | |

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|Focus is real | |

|Focus is virtual | |

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|It is a converging lens | |

|It is a diverging lens | |

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|Question (25): Draw a ray diagram to show the refraction of light when it passes through the | |

|optic centre of a convex lens. | |

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|Answer:  | |

|[pic] | |

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|Question (26): List out the uses of convex lenses. | |

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|Answer:  Convex lenses are used a) as a magnifying glass b) in photocopying cameras c) as the | |

|objective lens of a microscope and a telescope d) in theatre spot lights | |

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|Question (27): With the help of a ray diagram show how an object gets magnified in a simple | |

|microscope. | |

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|Answer:  | |

|[pic]When an object is placed between O to F1 we get an enlarged and erect image of the object. | |

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|Question (28): Define the power of a lens. What is its unit? | |

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|Answer:  Power of a lens is defined as the reciprocal of its focal length. The unit of power is | |

|dioptre. | |

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|Question (29): With the help of a diagram explain how light gets refracted when it passes through| |

|a rectangular glass slab. | |

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|Answer:  | |

|Place a rectangular glass slab on a white sheet of paper fixed on a drawing board. | |

|Trace the boundary ABCD of the glass slab. | |

|Remove the glass slab. Draw an incident ray IO on AB. | |

|Draw the normal NN1 at the point of incidence O | |

|Fix two pins P and Q on the incident ray IO. | |

|Place the glass slab within its boundary ABCD. | |

|Looking from the other side of the glass slab fix two pins R and S such that your eye and the | |

|feet of all the pins are in one straight line. | |

|Remove the glass slab and the pins. Mark the pin points P1, P2, P3 and P4. | |

|Join OO1.It is the refracted ray. | |

|Measure [pic]are the angle of incidence, angle of refraction and angle of emergence respectively.| |

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|[pic] | |

|Extend O1E backwards. The emergent ray is parallel to the incident ray. | |

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|[pic] | |

|The above experiment shows that | |

|When a ray light is passing from air to glass, that is, from a rarer medium to a denser medium, | |

|the refracted ray bends towards the normal drawn at the point of incidence. In this case [pic]But| |

|when the ray of light is passing from glass to air, that is, from a denser to a rarer medium the | |

|refracted ray bends away from the normal. In this case [pic] | |

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|Question (30): An object is placed at a distance of 50 cm from a concave lens of focal length 20 | |

|cm. Find the nature and position of the image. | |

| | |

|Answer:  The distance between the object and the lens (u) = -50 cm | |

|Focal length f = -20 cm | |

|Distance of the image from the optic centre = v | |

|[pic] | |

|The image is formed 14.3 cm from the lens on the same side as the object and since v is negative | |

|the image formed is virtual and erect. | |

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|Question (31): An object is placed 50 cm from a lens which produces a virtual image at a distance| |

|of 10 cm in front of the lens. Draw a diagram to show the formation of image and calculate the | |

|focal length of the lens. | |

| | |

|Answer:  Distance between the object and the lens = -50cm | |

|Distance between the image and the lens = -10cm | |

|Focal length = ? | |

|[pic] | |

|[pic] | |

|[pic] | |

|[pic] | |

|[pic] | |

|[pic] | |

|The focal length of the lens is -12.5 cm and the negative sign indicates that the lens is | |

|concave. | |

|[pic] | |

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|Question (32): An object of height 4 cm is placed at a distance of 10 cm from a convex lens of | |

|focal length 20 cm. Find the position, nature and size of the image. | |

| | |

|Answer:  Distance between the object and the lens u = -10cm | |

|Focal length = f = 20 cm | |

|Distance between the image and the lens v = ? | |

|[pic] | |

|[pic] | |

|[pic] | |

|[pic] | |

|[pic] | |

|[pic] | |

|[pic] | |

|The image is formed on the same side as the object and since v is negative the image is erect and| |

|virtual and is formed at a distance 20 cm in front of the lens. We know that | |

|[pic] | |

|height of the object ho = 4 cm | |

|[pic] | |

|[pic] | |

|[pic] | |

|[pic] | |

|Height of the image = 8 cm | |

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|Question (33): What is the power of a lens having a focal length of a) 50 cm b) -50cm | |

| | |

|Answer:  | |

|[pic] | |

|When f = 50 cm | |

|[pic] | |

|[pic] | |

|[pic] | |

|When f = -50 cm | |

|[pic] | |

|[pic] | |

|[pic] | |

|[pic] | |

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|Question (34): Draw a ray diagram to show the position and nature of the image formed by a convex| |

|lens when the object is placed | |

|a) at 2F1 | |

|b) between F1 and 2F1 | |

|c) beyond 2F1 | |

| | |

|Answer:  a) at 2F1 | |

|[pic] | |

| | |

|b) between F1 and 2F1 | |

|[pic] | |

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|c) beyond 2F1 | |

|[pic] | |

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|Question (35): State and verify Snell's law. | |

| | |

|Answer:  Snell's law states that for any two given pair of media, the ratio of the sine of the | |

|angle of incidence to the sine of the angle of refraction is a constant. | |

|• Place a rectangular glass slab on white sheet of paper fixed on a drawing board. | |

|• Trace the boundary ABCD of the glass slab. | |

|• Remove the glass slab and draw a normal N 1 N 2 at O. | |

|• Draw a straight line IO inclined at an angle say 30 o with the normal. IO is the incident ray.| |

| | |

| | |

|[pic] | |

|Fix two pins P and Q on the incident ray IO. | |

|Place the glass slab within its boundary ABCD. | |

|Looking from the other side of the glass slab fix two other pins R and S such that P, Q, R and S | |

|appear to lie on the same straight line. | |

|Remove the glass slab and the pins. Mark the pin points P, Q, R and S. | |

|Join the pins R and S and produce the line on both sides. The ray O 1 E is the emergent ray. | |

|Join OO 1 . It is the refracted ray. | |

|With O as centre, draw a circle of a convenient radius 'r' in such a way that it cuts the | |

|incident and the refracted rays at F and G respectively. | |

|From F and G draw perpendiculars to the normal N1N2. | |

|Δ FHO and Δ GKO are right angled triangles. | |

|[pic] | |

|Measure the length of FH and GK. | |

|Repeat the experiment for different values of angle of incidence. | |

|Record the result in a tabular form | |

|S. No | |

|I | |

|FH | |

|GK | |

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|[pic] | |

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|1 | |

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|2 | |

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|3 | |

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|4 | |

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|5 | |

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|Find the values of | |

|[pic]for different values of I. | |

|[pic]Will be a constant verifying | |

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