PREPARATORY EXAMINATION 2018 - Crystal Math
PREPARATORY EXAMINATION 2018
MARKING GUIDELINES
10611
MATHEMATICS (PAPER 1)
14 pages
GAUTENG DEPARTMENT OF EDUCATION PREPARATORY EXAMINATION
MATHEMATICS (Paper 1)
MARKING GUIDELINES
10611/18
1.1 1.1.1
1.1.2
QUESTION 1
x2 x 30 0
(x 6) x 5 0
x 6 or x 5 3x2 8x 4 0
b b2 4ac x
2a (8) (8)2 4(3)(4) x
2(3) x 3,10 or x 0,43
1.1.3
5 x x 1
5 x 1 x ( 5 x)2 (1 x)2
x2 3x 40 (x 4) (x 1) 0 x 4 or x 1 NA
1.1.4
6x2 3x 3x2 3
2x2 x 3x2 2x2 3x2 x 0 x2 x 0 x (x 1) 0 x 0 or x 1
OR
correct factors both answers correct
(2) standard form
correct subst. in the correct formula
x 3,10 x 0,43 Penalise for incorrect rounding off here only
(4)
isolate square root square both sides standard form
both answers correct choose correct answer
(5)
simplify
standard form correct factors critical values correct inequalities
2
6x2 3x 3x2 3
6x2 3x 9x2 6x2 9x2 3x 0 3x2 3x 0 3x(x 1) 0 x 0 or x 1
1.1.5
2x2 7. 2x 2
2 2.2 x
x
7.2 2
2
0
4.2 x
x
7.2 2
2
0
x
x
(4.22 1) (22 2) 0
2 x 2
1
4
x
or 22 2
x
22
22
NA
x 2 2 x 4
1.2 6x2 2 px 3x p 0 6x2 x(2 p 3) p 0 b2 4ac (2 p 3)2 4(6)( p) 4 p2 12 p 9 (2 p 3)2 = perfect square rational roots
10611/18
simplify
standard form correct factors critical values correct inequalities
(5)
standard form factors
x
22
22
NA
x = -4 (5)
coefficient of x
correct substitution in correct formula
factors = perfect square
(conclusion) (4)
[25]
3
QUESTION 2
2.1
Tn a (n 1) d
239 6 (n 1) (5)
239 6 5n 5
250 5n
n 50
2.2
T3 = ar2 = 18 ...
T5 = ar4 = 162 ...
? : r2 = 9 (r < 0)
r = 3 ar2 = 18
a(9) = 18
a = 2
Sn
a(r r
n 1) 1
2((3)7 1) S7 3 1
2(2187 1) 4
1 094
2.3 3; x; 11; 21; 35 x ? 3; 11 x; 10; 14 2x = 4 ? 14 2x = 10 x = 5
10611/18
Tn =?239 d = ?5
answer (3)
eq eq
r = 3
a = 2
correct substitution in correct formula
answer (6)
first difference d1 equating second
difference answer
(3)
4
2.4
S8 : S4 97:81
S8 97
S4 81
a1 r8 a1 r 4 97
1 r 1 r 81
a 1 r8 1 r 97
1 r a 1 r 4 81
1 r8 97 1 r 4 81
1 r 4 1 r 4 97
1 r 4
81
1 r 4 97 81
r 4 16 81
r 4 2 4 3
r 2 3
r 2 3
First three terms: 9; 6; 4
2.5.1
2( p 5) 2( p 5)2 2( p 5)3 ... r p5 Convergent: 1 r 1 1 p 5 1 4 p 6
2.5.2
S
a 1 r
1
1
(
1 2
)
2 3
5
10611/18
a1 r8 a1 r 4 97
1 r 1 r 81
simplify 1 r8 97 1 r 4 81
factors
r 4 2 4 3
r 2 3
first three terms (6)
r = p ? 5
1 p 5 1
4 p 6 (3)
substitute a = 1
r
1 2
answer (3) [24]
................
................
In order to avoid copyright disputes, this page is only a partial summary.
To fulfill the demand for quickly locating and searching documents.
It is intelligent file search solution for home and business.
Related download
- grade 12 mathematics paper 2 memo monday 27 august 2018
- euclidean geometry grade 12 caps
- math 12 pre calculus surrey connect
- 2019naeptransitionto dba and mode
- mathematics questionnaire 2018 grade pilot
- grade 12 september 2016 mathematics p2 st stithians college
- mathematics math ieb nsc grade 12 past exam 2018 p2
- preparatory examination 2018 crystal math
- national senior certificate nasionale senior setifikaat
- the nation s report card results from the 2019 grade 12
Related searches
- why is preparatory composition important
- 2018 sat math questions pdf
- examination results 2018 fiji
- university preparatory academy detroit
- 2018 2019 math state test
- university preparatory academy
- university preparatory academy redding ca
- national examination 2018 economics
- 2018 practice sat math test
- american preparatory academy skyward
- american preparatory schools utah
- american preparatory academy las vegas