MATHEMATICS Grade 12 - Western Cape

嚜獨estern Cape Education Department

Telematics

Learning Resource 2019

MATHEMATICS

Grade 12

Telematics Mathematics Grade 12 Resources

2

February to October 2019

Dear Grade 12 Learner

In 2019 there will be 8 Telematics sessions on grade 12 content and 6 Telematics sessions on grade

11 content. In grade 12 in the June, September and end of year examination the grade 11 content

will be assessed. It is thus important that you compile a study timetable which will consider the

revision of the grade 11 content. The program in this book reflects the dates and times for all grade

12 and grade 11 sessions. It is highly recommended that you attend both the grade 12 and 11

Telematics sessions, this will support you with the revision of grade 11 work. This workbook

however will only have the material for the grade 12 Telematics sessions. The grade 11 material

you will be able to download from the Telematics website. Please make sure that you bring this

workbook along to each and every Telematics session.

In the grade 12 examination Trigonometry will be + 50 marks and the Geometry + 40 marks of the

150 marks of Paper 2.

Your teacher should indicate to you exactly which theorems you have to study for examination

purposes. There are altogether 6 proofs of theorems you must know because it could be examined.

These theorems are also marked with (**) in this Telematics workbook, 4 are grade 11 theorems

and 2 are grade 12 theorems. At school you should receive a book called ※Grade 12 Tips for

Success§. In it you will have a breakdown of the weighting of the various Topics in Mathematics.

Ensure that you download a QR reader, this will enable you the scan the various QR codes.

At the start of each lesson, the presenters will provide you with a summary of the important

concepts and together with you will work though the activities. You are encouraged to come

prepared, have a pen and enough paper (ideally a hard cover exercise book) and your scientific

calculator with you.

You are also encouraged to participate fully in each lesson by asking questions and working out the

exercises, and where you are asked to do so, sms or e-mail your answers to the studio.

Remember:§ Success is not an event, it is the result of regular and consistent hard work§.

GOODLUCK, Wishing you all the success you deserve!

Telematics Mathematics Grade 12 Resources

3

February to October 2019

2019 Mathematics Telematics Program

Day

Date

Time

Grade

Subject

Topic

Term 1: 9 Jan 每 15 March

Tuesday

12 February

15:00 每 16:00

12

Mathematics

Trigonometry Revision

Wednesday

13 February

15:00 每 16:00

12

Wiskunde

Trigonometrie

Hersiening

TERM 2: 2 April to 14 June

Monday

8 April

15:00 每 16:00

12

Mathematics

Trigonometry

Tuesday

9 April

15:00 每 16:00

12

Wiskunde

Trigonometrie

Wednesday

15 May

15:00 每 16:00

11

Mathematics

Geometry

Thursday

16 May

15:00 每 16:00

11

Wiskunde

Meetkunde

Wednesday

22 May

15:00 每 16:00

12

Mathematics

Geometry

Thursday

23 May

15:00 每 16:00

12

Wiskunde

Meetkunde

Term 3: 9 July 每 20 September

Monday

29 July

15:00 每 16:00

12

Mathematics

Differential Calculus

Tuesday

30 July

15:00 每 16:00

12

Wiskunde

Differentiaalrekening

Wednesday

07 August

15:00 每 16:00

11

Mathematics

Functions

Monday

12 August

15:00 每 16:00

11

Wiskunde

Funksies

Term 4: 1 October 每 4 December

Tuesday

15 October

15:00 每 16:00

11

Mathematics

Paper 1 Revision

Wednesday

16 October

15:00 每 16:00

11

Wiskunde

Paper 2 Revision

Telematics Mathematics Grade 12 Resources

4

February to October 2019

Session 1: Trigonometry

x

Definitions of trigonometric ratios:

o

In a right-angled '

Sin T

opposite

hypotenuse

CosT

adjacent

hypotenuse

hypotenuse

opposit

Sin T

y

r

CosT

x

r

TanT

y

x

T

adjacent

opposite

adjacent

TanT

x

o On a Cartesian Plane

0∼, 90∼, 180∼, 270∼, 360∼ can be

y

x

30∼, 45∼ and 60∼ can be

obtained from the following unit circle

T

.

obtained from the following

90q

y

r, the radius is

1 since it is a

unit circle

(0 ; 1)



180q



(-1 ; 0)

(1 ; 0) x

T

T

T

270q

3

cos 45q = 1

T Tan is +ve in the3rd

quadrant

Sine

S

All

Tan

+

Cos

180q+T

becomes

T = 60q

3

2

sin 60q =

2

cos 60q = 1 2

tan 45q = 1

3

T

180q- T

S Sine is +ve in the

2nd quadrant

1

T = 45q

sin 45q = 1

2

1

45q

T =30q

sin 30q = 1 2

tan 30q = 1

45q

2

3

60q

1

cos 30q =

The ※CAST§ rule enables you to obtain the

sign of the trigonometric ratios in any of the

four quadrants.

y

The trigonometric function of angles

(180q㊣T) or (360q㊣T) or (-T)

30q

2

0q

360q

(0 ; -1)

x

r

T

x

Special Angles

o

T

y

tan 60q =

2

3

A - ALL trig

ratios are +ve in

the first quadrant

x

C Cos is +ve in

the 4nd quadrant

360q-T



Trigonometric function of T

The sign is determined by

the ※CAST§ rule.

(180q  T )

(180q  T )

(360q  T )

(360q  T )

(T )

sin(180q  T ) sin T

sin(180q  T )

 sin T

sin(360q  T )

 sin T

sin(360q  T ) sin T

sin(T )

 sin T

cos(180q  T )

 cos T

cos(180q  T )

 cos T

cos(360q  T )

 cos T

cos(360q  T ) cos T

cos(T )

 cos T

tan(180q  T )

 tan T

tan(180q  T )

 tan T

tan(360q  T )

 tan T

tan(360q  T )

tan( T )

 tan T

tan T

Telematics Mathematics Grade 12 Resources

x

February to October 2019

TRIGONOMETRIC IDENTITIES

tan T

x

5

sin T

cosT

(cosT z 0)

sin 2 T  cos 2 T

Co-functions or Co-ratios

sin(90q  T )

cosT

cos(90q  T )

sin T

sin 2 T

1,

1  cos 2 T ,

r

T

x

Determine the

Reference angle

Establish in

which two

quadrants 牟 is.

Calculate 牟 in

the interval

[0q; 360q]

Write down the

general solution

2.

3.

4.

sin(90q  T )  cos T

cos(90q  T )  sin T

x

Trigonometric Equations

sin T

1.

90q-T y

cos 2 T 1  sin 2 T

cos T

0,707

tan T

0,866

1

1

Reference ? = sin (0,707) = 45q

Reference ? = cos (0,866) = 30q

Reference ? = tan 1 (1) = 45q

? 牟 = 45q

or

牟 = 180q - 45q

? 牟 = 180q- 30q or 牟 = 180q + 30q

? 牟 = 180q - 45q

? 牟 = 45q

or

牟 = 135q

? 牟 = 150q or

牟 = 210q

? 牟 = r150q

? 牟 = r150+ k360? where k ? =

? 牟 = 135q

? 牟 = 45q+ k360? or

牟 = 135q + k360? where k ? =

1

? 牟 = 135q+ k180? & k ? =

TRIGONOMETRIC GRAPHS

Sine Function

Cosine Function

Tangent Function

Equation

Shape

a>0

a ................
................

In order to avoid copyright disputes, this page is only a partial summary.

Google Online Preview   Download