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CHEMICAL ENGINEERING DEPARTMENTGOVERNMENT POLYTECHNIC GANDHINAGARASSIGNMENT – 1Sub: IS (3330503)Semester – 3Unit: 1 – UNIT SYSTEMSTopic: 1.2 Dimensions and System of Units Two Marks Questions:Give the dimensions and unit for MKS system for fundamental quantities. Give the dimensions and unit for CGS system for fundamental quantities.Give the dimensions and unit for SI system for fundamental quantities.Three or Four Marks Questions:Describe System of units like MKS, CGS, SI, FPS ic: 1.3 Fundamental Quantities of Units, Derived UnitsTwo Marks Questions:Define physical quantities.Define Base units.Define Derived units. Three or Four Marks Questions:Explain Fundamental Quantities and Derived quantities with 3 examples of each. Topic: 1.4 Definition of UnitsTwo Marks Questions:Define the following derived units. Force, Pressure, Work, Heat, Power, EnergyTopic: 1.5 Unit ConversionTwo Marks Questions:Convert the following.15 m3/sec into lit/sec 5 kCal into Btu15 Kg to lbm 600 mmHg to atm 500 Psi into Kgf/m250 oF to oC 180 Joule to Calorie 7 atm to N/m230?C into Rankine 450 Liter to m31000 Watt to HP 500 Watt to HP-40?F into ?C 3 m2 to ft240 N to Kgf 3 Kcal to Joule 50 m2 to ft23.5 m3 to Liter 6 Kgf to Newton 20 Kg to Pound 5 atm to N/m2200 Watt to HP 3 Kcal to Joule 20 Kg to Pound10 lit to cm32 atm to N/m22 g/cm3 to Kg/ m3 150 J to Calorie 3.5 hp to Watt10 kgf to Newton2 g/cm3 to Kg/ m33.5 hp to Watt 1400 mm Hg into atm.Three or Four Marks Questions:A rectangular tank having dimensions 4 m x 2 m x 5 m is filled with acid of density 1.2 in C.G.S units. Calculate mass of acid in tank.Give the freezing point and boiling point of water into o C, o R, o F, and K.Give the human body temperature into o C, o R, o F, and K.In a double effect evaporator plant, the second effect evaporator is maintained under vacuum of 475 torr (mm Hg). Find the absolute pressure in kPa, bar and psi.The diameter and the height of vertical cylindrical tank are 5 ft and 6 ft 6 in respectively. It is full up to 75% height with carbon tetra chloride, the density of which is 1.6 kg/L. Find mass in kilogram.CHEMICAL ENGINEERING DEPARTMENTGOVERNMENT POLYTECHNIC GANDHINAGARASSIGNMENT – 2Sub: IS (3330503)Semester – 3Unit: 2 – BASIC CHEMICAL CALCULATIONSTopic: 2.1 & 2.2 Definition and Calculation of Mole, Atomic Weight, Molecular Weight, Equivalent Weight, Specific GravityTwo Marks Questions:Define the following with equation (If possible) – Mole, Atomic Weight, Molecular Weight, Equivalent Weight, Specific GravityFind out the Molecular Weight of following.Phenol H2SO4 Na2CO3 H3PO4 KMnO4 Calculate equivalent weight of following. H2SO4 Na2CO3 H3PO4 KMnO4Al2 (SO4)3Calculate number of moles of 54 kg water.Convert 88 kg of carbon dioxide into mole.Convert 499 gram of CaSO4.5H2O into mole.Find moles of K2CO3 will contain 117 kg of K.Find out gram of carbon present in 264 g of ic: 2.3 Composition of Solids by weight % and mole %Three or Four Marks Questions:Calculate the available nitrogen (N2) in urea100 gm Ethanol (C2H5OH) and 200gm Methanol (CH3OH) is dissolved in 500 ml of Water. Find Molar Composition of this Solution.500 grams of acetic acid is mixed with 1 liter of water. Find weight ratio and mole ratio of acetic acid.Mixed acid containing 40 % HNO3, 43% H2SO4 and 17% H2O is prepared by mixing 98% H2SO4 and HNO3 of unknown strength. Find out strength of unknown HNO3 and weight ratio of H2SO4 and HNO3 mixed. All percentages are by mass.The available nitrogen (N) in urea sample is found to be 45% by weight. Calculate the actual urea content in the sample. Ethanol and water form azeotrope containing 96% ethanol by weight. Find composition by mole %. Find total available nitrogen content in aq. solution having 30 % Urea (NH2CONH2), 20% ammonium sulphate ((NH4)2 SO4) and 20% ammonium nitrate (NH4NO3).All percentages are by ic: 2.4 Molarity, Normality, Molality, gm/liter and related simple numericalTwo Marks Questions:Define the following with equation (If possible) – Normality, Molarity, MolalityConvert 0.1 N to H2SO4 to Molarity.Do following conversion.294 gm/liter H2SO4 to Normality5N H3PO4 to gm/liter54.75gm/liter HCl to molarity3 M K2SO4 to gm/liter4.8 gm/liter to Norlamity Three or Four Marks Questions:Calculate the mass of K2SO4 required to prepare 2 liter 0.25 N and 0.5 M aqueous solutions.I want to prepare 2 liter 0.25 N and 0.25 M aqueous solutions of Na2SO4. Calculate the mass of Na2SO4 required in both cases. Also calculate gm/liter of Na2SO4 in these solutions.Calculate the mass of K2CO3 required in grams to prepare 1500 ml aqueous (1) 0.5 Normal solution (2) 0.7 Molar solution, (3) 0.8 Molal solution, if the density of solution is 1.12 gm/ccConvert 294 grams per liter sulphuric acid in to Normality and Molarity.A H2SO4 solution has a molarity of 11.24 and molality 94. Calculate the density of solution.An aqueous solution of K2CO3 is prepared by dissolving 43 kg of K2CO3 in 100 kg of water. Calculate the normality and molarity of solution. Density of solution is 1.3 kg/liter. GOVERNMENT POLYTECHNIC GANDHINAGARASSIGNMENT – 3Sub: IS (3330503)Semester – 3Unit 3: Ideal Gas LawTwo Marks Questions:State Ideal Gas Law. (Topic 3.2)What are STP & NTP conditions? (Topic 3.3) Define partial pressure. (Topic 3.4)State Daltan’s Law. (Topic 3.4)State Amagat’s Law. (Topic 3.4)Write down the equation for Average molecular weight & Density for gaseous mixture. (Topic 3.6) Three or Four Marks Questions:Derive equation for Ideal gas law. or Prove that PV = nRT. (Topic 3.2)Prove that Mole % = Pressure % (Topic 3.5)Obtain Value of Universal gas constant R in SI unit. (Topic 3.2)State Dalton’s law and Amagat’s law. (Topic 3.4)Prove that mole % = Volume % = pressure % for ideal gas. Or Derive the relation between mole % , weight %, & pressure % for ideal gas. (Topic 3.5)Problem: A gas mixture has SO2= 17.2%, O2=10.2 % and rest N2 by mass. Find average molecular weight and density of mixture at 473 K and 304 Kpa absolute pressure. (Topic 3.6)Calculate the volume occupied by 20 kg of chlorine gas at a pressure of 100 KPa and 298 deg K. (Topic 3.2)A gas mixture has SO2= 27.2%, O2=20.2 % and rest N2 by mass. Find average molecular weight and density of mixture at 473 K and 304 Kpa absolute pressure. (Topic 3.6) Calculate density of hydrogen gas at 101 kPa and 150. (Topic 3.2)A gas contain Hydrogen 80%, Oxygen 10% and Carbon dioxide 10% by volume. Calculate composition in weight %. (Topic 3.4)Calculate density of Nitrogen at 300 C and 2 atm. Pressure. (Topic 3.2)Find value of gas constant R, take number of moles in gmmole, pressure in atm, volume in cm3 and temperature in K. Assume that at STP 1 gmole gas occupies 22.4 liter. (Topic 3.2)A mixture of gases has following composition by mass O2 :16%, CO :4%, CO2 :17% and N2 :63%. Calculate the molar composition and average molecular weight of gas mixture. (Topic 3.4)Calculate the volume of 3 Kg Sulfur trioxide gas in liter at 30 lb/in2 pressure and 110 0 F temperature. (Topic 3.2) A gas mixture has the composition CH4 = 66%, CO2=30 % and rest NH3 = 4 % by volume. Find average molecular weight and density of mixture at 303 K and 202.65 Kpa. (Topic 3.6) CHEMICAL ENGINEERING DEPARTMENTGOVERNMENT POLYTECHNIC GANDHINAGARASSIGNMENT – 4Sub: IS (3330503)Semester – 3Unit 4 & 5: Material Balance without and Chemical Reaction2 marks:Define following 1. Limiting reactant 2. Excess reactant 3. Conversion 4. Yield 5. Recycling 6. Bypass 7. Material balance3 & 4 marksExplain recycling and bypassing operations with their significance. Or Short note on: Recycle and By-passProblems: Mixed acid containing 40 % HNO3, 43% H2SO4 and 17% H2O is prepared by mixing 98% H2SO4 and HNO3 of unknown strength. Find out strength of unknown HNO3 and weight ratio of H2SO4 and HNO3 mixed. All percentages are by mass. The gas phase reaction A = 2B + C occurs at constant temperature and pressure. Starting with 75 % A and 25% inert (on volume basis) in specified time volume doubles. Calculate % conversion of A achieved.In Ammonia synthesis nitrogen flows at rate of 25 kmol/h. Calculate stoichiometric proportion of hydrogen required and kg of ammonia produced for 25 % conversion.A feed to distillation tower contains28% benzene and 72% toluene. Distillate contains 52% benzene and bottom contains 5% benzene. Calculate mass flow rate of distillate and bottom for 1000 Kg of feed per hour. All percentages are by mass. How much heat must be added in order to raise the temperature of a 20% (W/W) Caustic soda solution from 280 K (7?C) to 360 K (87? C).The gaseous reaction A →2B+C takes place isothermally in a constant pressure reactor starting with a mixture of 75% A and 25% inert (by volume) ,in a specifically time the volume doubles Calculate the conversion achieved.A solution of ethyl alcohol(C2H5OH) containing 10% alcohol is fed at the rate of 2000 kg/hr. to a distillation column. The top product contains 95% alcohol. The bottom product contains 1% alcohol. Calculate the mass flow rate of top and bottom products and percentage loss of alcohol in residue.A sample of groundnut seeds contains 45% oil, 45% solids and rest moisture. The resultant cake contains 80% solids, 5%oil and rest moisture. Find the percentage recovery of oil.Chlorine gas is manufactured from NaCl by following reaction 2NaCl + 2H2O → 2NaOH + Cl2(g) + H2(g) If 50 kg of NaCl reacts with 10 kg H2O, find (1) Limiting reactant (2) Composition of final product if the reaction is 60% complete. In a textile mill, a double effect evaporator concentrates weak liquor containing 4%(wt.) Caustic soda (NaOH) to produce a solution containing 25% solids. Calculate the Kg of water evaporated per 100 Kg feed in the evaporator. The analysis of limestone is 84.5 % CaCO3, 11.5 % MgCO3 and rest inert. Limestone decomposes during calcinations at high temperature: CaCO3 → CaO + CO2(g) MgCO3 → MgO + CO2(g) If the calcinations is 90% complete calculate the mass of CO2 produced per 100 kg of limestone calcined.100 m3 of Ammonia gas at 250 C and 750 mmHg pressure is absorbed by 20% aqueous sulphuric acid to produce aqueous Ammonium sulphate Calculate (1) Amount of Ammonium sulphate formed (2) Amount of 20% Sulphuric acid requiredSoyabean seeds are extracted with hexane. The flaked seeds contain 18.6% oil, 69% solids and 12.4% moisture. After extraction cake is separated from hexane<oil solution. Cake contains 0.8% oil, 87.7% solids and 11.5% Moisture. All percentages are by weight. Find the percentage recovery of oil by extraction.An aqueous solution of 10% Ethanol is distilled. The distillate stream is 10% of feed and contains 60% Ethanol. Calculate flow rate and composition of bottom stream. If 60 kg of Crystal containing 8.2% moisture is dried to 0.4 % moisture. Calculate the amount of water evaporated.A distillation column separates an ethyl alcohol – water feed into high purity ethyl alcohol and waste water. The feed has a composition of 20 % ( by mole) ethyl alcohol. The distillate contain 85%( mole) while residue contain 3% (mole) alcohol concentration. Calculate: The quantities of distillate and residue for 100 Kg.mole/ hr of feed. Percentage recovery of alcohol in distillate. Groundnut seeds contain 48% oil, 45% solids and rest moisture. The resultant cake contains 82% solids, 3% oil and rest moisture. Find the percentage recovery of oil.A solution of ethyl alcohol (C2H5OH) containing 20% alcohol is fead the rate of 1500 kg/hr to a distillation column. The top contains 95% alcohol. The residue contains 4% alcohol. Calculate percentage loss of alcohol in residue.Seeds contain 18.6% oil, 69 % solids and 12.4% moisture. They are extracted with hexane. Cake has 0.8% oil, 87.7% solids and 11.5% moisture. Calculate percentage recovery of oil.100 kg weak liquor containing 4% Caustic soda is concentrated to 25% soda, Calculate mass of water evaporated.If 50 moles of CO is fed with 60 moles of steam in a shift reactor: CO + H2O = CO2 + H2, calculate composition of product gas (dry) mixture at 95% conversion of limiting reactant. A Solution of 70% Benzene and 30% Toluene is distilled to give distillate having 95% Benzene and residue having 90% Toluene. Calculate quantities of top and bottom product for 150 Kmole feed.Acetylene reacts with water: C2H2 + H2O = CH3CHO. At 55% conversion and 95% yield calculate amount of Aldehyde formed per 1 ton Acetylene. ................
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