Mole conversions and stoichiometry worksheet
Chem 1020 Mole conversions and stoichiometry worksheet
1. How many Ag atoms are in 2.43 mol Ag atoms?
2.43 mol Ag atoms ? 6.022?1023 Ag atoms = 1.46?1024 Ag atoms 1 mol Ag atoms
2. How many Br2 molecules are in 18.2 mol Br2 molecules?
18.2
mol
Br2
molecules ?
6.022 ?1023 Br2 molecules 1 mol Br2 molecules
= 1.10?1025
Br2
molecules
3. 7.53 ? 1028 Al atoms is equal to how many mol Al atoms?
7.53?1028
Al
atoms ?
1 mol Al 6.022 ?1023
atoms Al atoms
= 1.25?105
mol
Al
atoms
4. 2.932 ? 1017 H2O molecules is equal to how many mol H2O molecules?
2.932 ?1017
H2O
molecules
?
1 mol H2O 6.022?1023 H
molecules 2O molecules
=
4.869 ?10-7
mol
H2O
molecules
5. How many mol N atoms are in 8.3 mol HCN?
8.3 mol HCN ? 1 mol N atoms = 8.3 mol N atoms 1 mol HCN
6. How many mol H atoms are in 2.63 mol CH2O?
2.63
mol
CH2O ?
2 mol H atoms 1 mol CH2O
=
5.26
mol
H
atoms
7. How many Cl atoms are in 3.63 mol CH2Cl2?
3.63
mol
CH2Cl2
?
2 mol Cl atoms 1 mol CH3Cl2
?
6.022 ?1023 1 mol Cl
Cl atoms atoms
=
4.37 ?1024
Cl
atoms
8. How many O atoms are in 6.229 mol Ca(NO3)2?
6.229
mol
Ca(NO3 )2
? 6 mol O atoms 1 mol Ca(NO3 )2
?
6.022?1023 O atoms 1 mol O atoms
=
2.251? 10 25
O
atoms
9. How many mol FeCl3 are in 15.3 g FeCl3?
Molar mass FeCl3 = 55.85 + 3(35.45) = 162.2 g/mol
15.3
g
FeCl3
?
1 mol FeCl3 162.2 g FeCl3
=
0.0943
mol
FeCl3
10. How many mol Na2CO3 are in 23.5 g Na2CO3?
Molar mass Na2CO3 = 2(22.99) +12.01+ 3(16.00) = 105.99 g/mol
23.5
g
Na
2CO3
?
1 mol 105.99
Na 2CO3 g Na2CO3
=
0.222
g
Na 2 CO3
11. What mass is 3.52 mol NaNO3?
Molar mass NaNO3 = 22.99 +14.01+ 3(16.00) = 85.00 g/mol
3.52
mol
NaNO3
?
85.00 g NaNO3 1 mol NaNO3
=
299
g
NaNO3
12. What mass is 7.326 mol C2H4?
Molar mass C2H4 = 2(12.01) + 4(1.008) = 28.052 g/mol
7.326
mol
C2H4 ?
28.052 g C2H4 1 mol C2H4
=
205.5
g
C2H4
13. How many mol H atoms are in 18.2 g NH3?
Molar mass NH3 = 14.01+ 3(1.008) = 17.034 g/mol
18.2
g
NH3
? 1 mol 17.034
NH3 g NH3
?
3
mol H atoms 1 mol NH3
=
3.21
mol
H
atoms
14. How many mol O atoms are in 3.52 g MnO2?
Molar mass MnO2 = 54.94 + 2(16.00) = 86.94 g/mol
3.52
g
MnO2
?
1 mol MnO2 86.94 g MnO2
?
2 mol O atoms 1 mol MnO2
=
0.0810
mol
O
atoms
15. How many S atoms are in 2.35 g Al2S3?
Molar mass Al2S3 = 2(26.98) + 3(32.06) = 150.14 g/mol
2.35
g
Al2S3
? 1 mol Al2S3 150.14 g Al2S3
?
3 mol S atoms 1 mol Al2S3
?
6.022?1023 S atoms 1 mol S atoms
=
2.83?1022
S
atoms
16. How many F atoms are in 5.52 g C2H2F4?
Molar mass C2H2F4 = 2(12.01) + 2(1.008) + 4(19.00) = 102.036 g/mol
5.52
g
C2
H2
F4
?
1 mol 102.036
C2 H 2 F4 g C2H2
F4
?
4 1
mol mol
F atoms C2 H 2 F4
?
6.022 ?1023 F atoms 1 mol F atoms
= 1.30?1023
F
atoms
17. What mass of O is in 7.56 g H2O2?
Molar mass H2O2 = 2(1.008) + 2(16.00) = 34.016 g/mol Molar mass O = 16.00 g/mol
7.56
g
H2O2
?
1 mol 34.016
H2O2 g H2O2
? 1
2 mol O mol H2O2
? 16.00 g O 1 mol O
=
7.11
g
O
18. What mass of Cl is in 38.2 g PCl3?
Molar mass PCl3 = 30.97 + 3(35.45) = 137.32 g/mol Molar mass Cl = 35.45 g/mol
38.2
g
PCl3
?
1 mol 137.32
PCl3 g PCl3
?
3 mol Cl 1 mol PCl3
?
35.45 g Cl 1 mol Cl
=
29.6
g
Cl
For the following 6 questions, consider the following balanced chemical equation:
N2 + 3H2 2NH3
Molar mass N2 = 2(14.01) = 28.02 g/mol Molar mass H2 = 2(1.008) = 2.016 g/mol Molar mass NH3 = 14.01+ 3(1.008) = 17.034 g/mol
19. How many mol NH3 can be produced from 7.23 mol N2 (assuming H2 is in excess)?
7.23
mol
N2 ?
2 mol NH3 1 mol N2
= 14.5
mol
NH3
20. How many mol H2 must react with 3.26 mol N2?
3.26
mol
N
2
?
3 1
mol mol
H2 N2
= 9.78
mol
H2
21. How many grams of N2 must react if 25.0 g NH3 are formed?
25.0
g
NH
3
?
1 mol 17.034
NH3 g NH3
? 1 mol N2 2 mol NH3
? 28.02 g N2 1 mol N2
=
20.5
g
N2
22. How many grams H2 will react with 15.3 g N2?
15.3
g
N
2
?
1 mol N2 28.02 g N2
? 3 mol H2 1 mol N2
? 2.016 g H2 1 mol H2
= 3.30
g
H2
23. If 2.36 g N2 and 1.52 g H2 react together, what mass NH3 can be produced? Which is the limiting reactant?
2.36
g
N2
?
1 mol N2 28.02 g N2
? 2 mol NH3 ? 17.034 g NH3 1 mol N2 1 mol NH3
=
2.87 g NH3
1.52
g
H2 ?
1 mol H2 2.016 g H2
? 2 mol NH3 3 mol H2
? 17.034 g NH3 1 mol NH3
= 8.56
g
NH3
There is enough N2 to make 2.87 g NH3, and there is enough H2 to make 8.56 g NH3. N2 is the limiting reactant since it produces the smaller product mass. 2.87 g NH3 can be produced (this is the theoretical yield).
24. If 5.32 g N2 and 15.8 g H2 react together, what mass NH3 can be produced? Which is the limiting reactant?
5.32
g
N
2
?
1 mol N2 28.02 g N
2
? 2 mol NH3 1 mol N2
? 17.034 g NH3 1 mol NH3
=
6.47 g NH3
15.8
g
H2
?
1 mol H2 2.016 g H2
?
2 mol NH3 3 mol H2
? 17.034 g NH3 1 mol NH3
= 89.0
g
NH3
There is enough N2 to make 6.47 g NH3 and there is enough H2 to make 89.0 g NH3. N2 is the limiting reactant because it makes the smaller product mass. 6.47 g NH3 can be produced (this is the theoretical yield).
For the following 6 questions, consider the following balanced chemical equation:
2C2H2 + 5O2 4CO2 + 2H2O
Molar mass C2H2 = 2(12.01) + 2(1.008) = 26.036 g/mol Molar mass O2 = 2(16.00) = 32.00 g/mol
Molar mass CO2 = 12.01 + 2(16.00) = 44.01 g/mol Molar mass H2O = 2(1.008) + 16.00 = 18.016 g/mol
25. How many mol of CO2 can be formed if 8.26 mol C2H2 react (assuming excess O2)?
8.26
mol
C2
H2
?
4 2
mol mol
CO2 C2H2
= 16.5
mol CO2
26. How many mol C2H2 will react with 20.3 mol O2?
20.3
mol
O2
?
2 mol C2H2 5 mol O2
= 8.12
mol C2H5
27. How many g of H2O can be formed if 36.2 g C2H2 react (assuming excess O2)?
36.2
g
C2H2
?
1 mol 26.036
C2H2 g C2H2
?
2 mol H2O 2 mol C2H2
? 18.016 1 mol
g H2O H2O
=
25.0
g
H2O
28. How many g O2 will react with 12.2 g C2H2?
12.2
g
C2H
2
?
1 mol 26.036
C2H2 g C2H
2
? 5 mol O2 2 mol C2H2
? 32.00 g O2 1 mol O2
= 37.5
g O2
29. If 2.l3 g C2H2 and 3.63 g O2 react, how many grams CO2 can be formed? Which is the limiting reactant?
2.13
g
C2
H
2
?
1 mol 26.036
C2H2 g C2H
2
? 4 mol CO2 2 mol C2H2
? 44.01 g CO2 1 mol CO2
=
7.20 g
CO2
3.63
g
O2
?
1 mol O2 32.00 g O2
? 4 mol CO2 5 mol O2
? 44.01 g CO2 1 mol CO2
=
3.99 g CO2
There is enough C2H2 to make 7.20 g CO2 and there is enough O2 to make 3.99 g CO2. O2 is the limiting reactant since it produces the smaller product mass. 3.99 g CO2 can be produced (this is the theoretical yield).
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