CHEM 212 CH 12-16 Review 2014 - Pennsylvania State University
Study
Guide
for
Exam
2--
Aldehydes
and
Ketones
Oxidation
of
Alcohols
to
Carbonyl
Compounds
The
oxidation
of
alcohols
to
carbonyl
compounds
is
the
reverse
of
nucleophilic
addition
(below).
Most
oxidants
accept
the
alcohol
oxygen
as
a
nucleophile
followed
by
loss
of
the
acidic
hydrogen.
The
process
is
completed
by
an
E2--like
elimination
of
hydrogen
from
the
proto--carbonyl
carbon
in
concert
with
formation
of
the
C=O
--bond
and
reductive
loss
of
the
leaving
group.
General
Mechanism
H
O
Ox
H
H O Ox H
B
H
-H+
O Ox
BH O
Ox
Swern
H O H
Cl S Me Me
H
O
Me S
-HCl
H Me
B
H
Me
OS
Me
BH O
Me S
Me
Chromic
Acid
H O H
O Cr O O
B
H
O
H+
O Cr O xfer
HO
H
OH
O Cr O
O
BH O
OH Cr O O
Scope
and
Limitations
1. As
a
hydrogen
atom
is
needed
for
the
elimination
step,
3o
alcohols
do
not
oxidize
to
carbonyl
compounds.
2. Normally
1o
alcohols
are
converted
to
aldehydes
and
2o
alcohols
to
ketones.
3. However,
in
the
presence
of
water,
aldehydes
form
hydrates
that
undergo
more
rapid
oxidation
than
the
starting
1o
alcohols.
Thus
with
CrO3/H2SO4,
Na2CrO7,
K2CrO7,
H2CrO4,
1o
alcohols
are
converted
to
carboxylic
acids.
B
BH
R
O
H2O
H RO
H
HO H
O Cr O O
H
O
H+
R O Cr O xfer
HO H O
H
OH
R O Cr O
HO
O
R O
HO
4. This
over--oxidation
is
avoided
with
the
Swern
oxidation
or
the
use
of
PCC.
OH Cr O O
Nucleophilic
Addition
Most
of
the
reactions
of
aldehydes
and
ketones
in
these
chapters
are
nucleophilic
addition
reactions.
The
oxygen
in
C=O
polarizes
the
bond.
Therefore,
while
electrophilic
addition
(electrophile
first,
followed
by
nucleophile)
was
favored
for
the
comparatively
non--polar,
electron--rich
alkene,
carbonyls
undergo
nucleophilic
addition
(nucleophile
first,
followed
by
electrophile).
Note
how
all
the
mechanisms
begin
exactly
the
same
way:
General
Mechanism
O
O
E+
OE
Nu
Nu
tetrahderal intermediate
Nu
Hydride
LiAlH4
is
similar
O
H
HB
H
H
H3B O H
H OR
OH H
+ H3BOR
Carbanion
Grignard/Alkyllithium/Acetylide
O 1)
Br Mg R
BrMg O R
H HOH
2)
OH R
+ BrMgOH2
Ylide
Wittig
Reaction
O Ph3P CH2
O Ph3P CH2
O Ph3P CH2
O PPh3 + CH2
The
Wittig
is
unique
in
that
the
alkoxide
oxygen
in
the
tetrahedral
intermediate
attacks
the
phosphonium
center
forming
an
oxaphosphetane
intermediate.
Thus,
the
electrophile
is
not
H+
as
in
the
previous
examples
but
the
phosphonium
center.
The
intermediate
undergoes
a
reverse
2+2
process
to
form
triphenylphosphine
oxide
and
an
alkene
product
to
complete
the
process.
If
the
nucleophile
is
a
weaker
base
than
the
alkoxide
in
the
tetrahedral
intermediate,
an
alternative
mechanism
is
proposed.
Here,
the
electrophile
(usually
H+)
is
added
first
to
enhance
the
polarity
of
the
C=O
bond,
and
reduce
the
energy
of
the
tetrahedral
intermediate
(transition
state
resembles
this
intermediate;
stabilizing
it
will
increase
the
rate).
The
reverse
reaction
rates
are
also
enhanced,
so
the
mechanisms
feature
equillibria.
Alcohol
as
Nucleophile
?
Acetal/Ketal
Formation
O
H3O+ H O
HO
H+ xfer
HOR H O H -H2O
HOR -H3O+
OR
ROH
ROH
RO
RO
RO
RO
1o
Amine
as
Nucleophile
?
Imine
Formation
O
H3O+ H O
HO
H+ xfer H O H -H2O
RNH H
RNH H
RN H
2o
Amine
as
Nucleophile
?
Enamine
Formation
RN
O
H3O+ H O
HO
H+ xfer
H O H -H2O
H
RNH R
RNH R
RN R
Cyanide
as
Nucleophile
?
Cyanohydrin
Formation
O
HCN H O
HO
RN R
OH H
RN R
HOH H
NC
N C
Peracid
as
Nucleophile
?
Baeyer--Villager
Oxidation
O
H3O+ H O
HO
B:
H+ xfer
HO
BH O
OH OR
O
OH OR
O
O OR
O H
Developmental
Problems
1. Complete
the
following
`reactivity
tree'
for
a
ketone:
O OR HO
H3O+, H2O
ROH, H3O+
OH, HO
H 3O+ RNH 2, pH 5.5 R 2NH, pH 5.5
O Ph
NH2OH, pH 5.5
PPh 3
HCN, KCN 1) RMgBr
2) dil. H3O+
1) LiAlH4 2) dil H3O+
2. Predict
the
products:
a.
O
b.
O
c.
O
d.
1) LiAlH4
2) dil. H3O+
1) PhMgBr 2) dil. H3O+
H2C PPh3
e.
f.
g.
h.
i.
j.
OH Na2Cr2O7
HO
H 2SO 4/H2O
3. Predict
the
products
?
Part
II:
a.
O
mCPBA
CH2Cl2
b.
O
PPh 3
c.
O
Ag2O, KOH
H
d.
1) DIBAH, -78 oC
2) H3O+
O
O
e.
O 1) KCN, HCl
2) HCl, H2O
f.
1) DIBAH, -78 oC
2) H3O+
OO
g.
OH
1) (COCl)2, DMSO 2) Et3N
h.
OH
PCC
CH2Cl2
i.
1) Mg, ether
Br
2) O
3) H3O+ j.
O OO
NaBH4 EtOH
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