YEAR 9 CHEMISTRY MARKING SCHEME
[Pages:6]DEPARTMENT FOR CURRICULUM, LIFELONG LEARNING AND EMPLOYABILITY Directorate for Learning and Assessment Programmes Educational Assessment Unit
Annual Examinations for Secondary Schools 2021
Track 3
YEAR 9
CHEMISTRY
MARKING SCHEME
Item
1 a b c d e f g h
Answer and guidelines Section A
Liquid. E Boiling. 1500 1500 Tightly packed; strong forces of attraction between them; vibrating. This sample of iron is impure. Chemical.
Total
Marks
1 1 1 1 1 1 1 1 8
2 a b
False statements:
Elements can be split up into simpler substances by chemical methods.
1
Most elements are liquids or gases at room temperature.
1
Any two of:
? Shiny when freshly cut
? Good conductors of heat and electricity
? Relatively high melting point
? Relatively high density
2
? Malleable (can be hammered)
? Ductile (can be drawn into wires)
? Usually solid at room temperature
? Most metals are sonorous or make a bell-like sound when struck
Accept other suitable answers.
c i
1 mark for electron arrangement. 1 mark for number of protons in nucleus. 3 1 mark for number of neutrons in nucleus.
1 mark for electron arrangement.
ii
2
1 mark for charge.
Chemistry ? Marking Scheme ? Year 9 ? Track 3 ? 2021
Page 1 of 6
Item iii
d i
ii
iii e i
ii
Answer and guidelines
Ionic (electrovalent).
Diatomic elements exist as molecules composed of only two atoms of the
same type of element.
H2 + Cl2 2HCl
1 mark for formulae.
1 mark for balancing.
Covalent.
115B has one neutron more than 105B.
115B
Total
Marks 1 1
2
1 1 1 16
3 a i blue, CuSO4.5H2O
1,1
ii Calcium carbonate or CaCO3
1
b
C3H8 + 5O2 3CO2 + 4H2O
1
1 mark for drawing oxygen atoms
joined correctly.
1 mark for showing correctly shared
c
3
electrons.
1 mark for correct number of electrons.
Accept atoms touching each other.
d
Ozone protects the Earth's surface from excessive solar U.V. radiation
1
which causes cancer in living things.
Total 8
4 a
Check boiling point / melting point / density.
1
b i deliquescent.
1
ii efflorescent.
1
Sodium. c
1 Accept formula or other suitable answers.
Mg (s) + H2O (g) MgO (s) + H2 (g)
d
1 mark for formulae. 2
1 mark for balancing.
e
Chlorine.
1 Accept Cl2 or other suitable answers.
KOH f
Accept name or other suitable answers. 1
Sulfur dioxide. g
1 Accept formula.
h
Carbon monoxide.
1 Accept formula.
Total 10
Page 2 of 6
Chemistry ? Marking Scheme ? Year 9 ? Track 3 ? 2021
Item 5 a
b c d e
f
Answer and guidelines
A: Thistle funnel.
B: Gas jar.
C: Beehive shelf.
Zn + 2HCl ZnCl2 + H2
1 mark for formulae.
1 mark for balancing.
Expose the gas to a lighted wooden splint, gas burns with a `pop' sound.
To introduce the dilute acid into the reaction flask in a controlled manner.
OR Prevents the gas produced from escaping.
Hydrogen is insoluble in water.
Moles of Mg atoms = 92.31 / 24 = 3.85
Moles of H atoms = 7.69 / 1 = 7.69
Marks 1 1 1
2
1 1 1
1
Ratio Mg : H = 3.85 : 7.69 Divide by 3.85 to simplify ratio = 1 : 2 Empirical formula = MgH2
1 Total 10
6 a i strong; weak
2
neutralisation; soluble; hydroxide ii
Accept OH- instead of hydroxide.
3
sodium hydroxide solution: 13
sodium chloride solution: 7
dilute hydrochloric acid: 1
b
vinegar: 3
3
clean rainwater: 5/6
acid rain: 3/4
Do not accept values greater than 4.
? mark each.
Total 8
SECTION B
7 a i Sulfuric acid.
1
H2SO4 (aq) + Fe(OH)2 (s) FeSO4 (aq) + 2H2O (l)
1 mark for formulae.
ii
3
1 mark for balancing.
1 mark for state symbols.
iii To ensure all the acid has reacted.
1
iv If all the acid is used, the litmus paper should remain blue.
1
To prevent the formation of anhydrous iron(II) sulfate.
1
v A slower rate of evaporation allows for the formation of large hydrated
1
crystals.
Chemistry ? Marking Scheme ? Year 9 ? Track 3 ? 2021
Page 3 of 6
Item vi
Answer and guidelines
Marks
water bath tripod
1 mark for evaporating dish. 1 mark for drawing water bath.
1 mark for drawing tripod & Bunsen burner. 3
Deduct ? mark for each missing label.
b i Sodium hydrogen sulfate, NaHSO4
1
ii Acid salt.
1
c i Precipitation.
1
ii RFM Fe2(CO3)3 = (56 ? 2) + (12 ? 3) + (16 ? 9) = 292
1
73 / 292 = 0.25 moles
1
RFM FeCl3 = 56 + (35.5 ? 3) = 162.5
Fe2(CO3)3 : FeCl3 = 1 : 2
1
iii 292 g Fe2(CO3)3 would require (162.5 ? 2) g FeCl3
73 g Fe2(CO3)3 would require ? g FeCl3 (allow follow through)
1
(162.5 ? 2 ? 73) / 292 = 81.25 g FeCl3
(allow follow through)
1
iv Wash the residue (insoluble salt) with distilled water.
1
Total 20
8 a b
Manganese(IV) oxide. Catalyst. Hydrogen peroxide. H2O2
Accept any other reasonable answer. 1 1 1 1
c
Page 4 of 6
5
Trough
1 mark for drawing apparatus. 1 mark for correct assembly of apparatus. 3 marks for correct labelling of apparatus and chemicals.
Chemistry ? Marking Scheme ? Year 9 ? Track 3 ? 2021
Item d
e
Answer and guidelines
2H2O2(aq) 2H2O(l) + O2(g)
1 mark for formulae.
1 mark for balancing.
1 mark for state symbols.
RMF of Fe2O3 = 160 RMM of 3H2O = 54
1 mark for molar masses.
Total mass of 1 mole Fe2O3.3H2O = 214 g = 100% mass of 3H2O = 54 g = ?
1 mark for working.
Answer = 25.23%
1 mark for answer.
Marks 3
1
1 1
Method
Example of use
galvanising
car body
oiling f
painting
car engine 5
bridge
sacrificial protection
iron ship
plastic coating
wire fence 1 mark for each correct answer.
Total 20
Tear the leaves into very small pieces and place them into a mortar.
1
9 a i Add some alcohol and grind (crush) the leaves with a pestle until the
1
alcohol turns green as the chlorophyll is extracted.
ii Paper chromatography.
1
1 mark for chromatography paper.
1 mark for solvent.
1 mark for spot of chlorophyll.
1 mark for correct assembly of
iii
apparatus. 4
Deduct ? mark for each missing
label.
Accept alternative correct setups such as using a round chromatography
paper with a central spot of chlorophyll.
The four components of chlorophyll will separate by travelling different
1
distances from the base line up the paper.
iv
Carotenoids will travel the furthest distance.
1
Chlorophyll b will travel the least distance.
1
Fractionating column used in fractional distillation only.
1
b
Simple distillation is used to obtain the pure solvent from a solution. Fractional distillation is used to separate mixtures of miscible liquids
1 1
based on their different boiling points.
Chemistry ? Marking Scheme ? Year 9 ? Track 3 ? 2021
Page 5 of 6
Item c i
ii iii
Answer and guidelines
Mass of water removed = 4.92 ? 2.40 = 2.52 g
RMM of H2O = (1 ? 2) + 16 = 18
18 g = 1 mole H2O
2.52 g = ?
2.52 / 18 = 0.14 moles
RFM MgSO4 = 24 + 32 + (16 ? 4) = 120
120 g = 1 mole MgSO4
2.40 g = ?
2.40 / 120 = 0.02 moles
Ratio MgSO4 : H2O = 0.02 : 0.14
Simplify ratio
1 : 7
Formula = MgSO4.7H2O x = 7
Marks 1 1
1 1
1
1 1 Total 20
Page 6 of 6
Chemistry ? Marking Scheme ? Year 9 ? Track 3 ? 2021
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