Equations of motion for constant acceleration
Lecture 3
Chapter 2
Physics I
Equations of motion for constant acceleration
Course website:
PHYS.1410 Lecture 3 Danylov Department of Physics and Applied Physics
Today we are going to discuss:
Chapter 2:
Motion with constant acceleration: Section 2.4 Free fall (gravity): Section 2.5
PHYS.1410 Lecture 3 Danylov Department of Physics and Applied Physics
Finding Position from a Velocity Graph
Let's integrate it:
x
Initial position
Geometrical meaning
of an integral is an area
Total displacement
displacement
The total displacement s is called the "area under the velocity curve." (the total area enclosed between the t-axis and the velocity curve).
x f xi Area under v vs t betweenti and t f
PHYS.1410 Lecture 3 Danylov Department of Physics and Applied Physics
v(t) t
ConcepTest
Position from velocity
A) 20 m
Here is the velocity graph of an object that is at the origin (x = 0 m) at t = 0 s.
B) 16 m
At t = 4.0 s, the object's position is
C) 12 m
D) 8 m
E) 4 m
Displacement = area under the curve
Simplifications
Objects are point masses: have mass, no size In a straight line: one dimension
Point mass
Consider a special, important type of motion:
Acceleration is constant (a = const)
PHYS.1410 Lecture 3 Danylov Department of Physics and Applied Physics
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