Homework 10 Solutions - Statistics Department

Then, the average test score of n students is a random variable with mean 75 and variance 25/n. Also, note that having the class average be within 5 of 75 with probability at least 0.9 is equivalent to having the class average be more than 5 away from 75 with probability at most 0.1; hence, using Chebyshev’s inequality again, we have. ................
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