Problem 1: The Water Jugs Problem - Brooklyn College
Problem 1: The Water Jugs Problem
There are many real-world problems that can be can be solved by 1) understanding the problem well and 2) being able to reduce the problem into smaller problems which the learner is able to understand, solve, and manipulate as part of the process of solving a larger problem. One way of approaching a game or problem is to consider all the possible STATES of the problem space.
Let us consider the well-known Water Jugs Problem where we have a Four Gallon Jug of Water and a Three Gallon Jug of Water and a Water Pump. The challenge of the problem is to be able to put exactly two gallons of water in the Four Gallon Jug, even though there are no markings on the Jugs. Although this isn’t a “life-threatening” situation, one could easily conjure real life situations where there would be a need to have exactly two gallons in the Four Gallon Jug. Imagine, for example, we are dealing with gas for two motorbikes (perhaps on a desert journey) and only the two jugs were available whereby the both motorbikes need gas, and the bigger bike had a two gallon tank.
The ten possible states of the problem are listed on the next page. Working problems, their possible states, and sequences of possible steps to accomplish subgoals can be a very effective problem-solving method. It falls nicely into the paradigm that favors “learning by doing.” This is an example of a problem that we would like to address by developing a short programmed game, using the background and experience of one of our principle investigators. More important than the solution itself, is the process by which the student learner will develop his/her solution. We believe that through such approaches he/she will be more motivated than by conventional teaching learning styles, will learn problem-solving methods for life that will have far-reaching effects, and that such approaches can be applied to and will lead to better understanding for a variety of mathematical problems that students encounter.
Let us now consider a possible sequence of steps to solve this problem:
Fill Three Gallon Jug (State 3). Put Three Gallon Jug into Four Gallon Jug (State 5). Fill Three Gallon Jug (State 3). Put Three Gallon Jug into Four Gallon Jug (State 7). Now there are there are Four Gallons in the Four Gallon Jug and Two Gallons in the Three Gallon Jug. Now you just have to Empty the Four Gallon Jug (State 2) and Transfer the Two Gallons left in the Three Gallon Jug, into the Four Gallon Jug. (State 8)
Another possible solution: Beginning with the two empty jugs, fill the Four Gallon Jug (State 1). Transfer as much from the Four Gallon Jug into the Three Gallon Jug as possible, leaving the Four Gallon Jug with one gallon of water and the Three Gallon Jug full (State 6). Empty the Three Gallon Jug (State 4). Transfer the one gallon of water from the Four Gallon Jug to the Three Gallon Jug, leaving the Four Gallon Jug empty and the Three Gallon Jug with one gallon of water (State 9). Refill the Four Gallon Jug completely (State 1). Transfer as much from the Four Gallon Jug to the Three Gallon Jug as possible leaving the Four Gallon Jug with the required two gallons (State 10).
Four Gallon JUG Three Gallon Jug [pic] Three Gall
[pic]
-----------------------
(1) Fill Four Gallon Jug
(2) Empty Four Gallon Jug
(3) Fill Three
Gallon Jug
(4) Empty Three Gallon Jug
(5) Three Gallon into
Four Gallon
(6) Four Gallon into Three Gallon Jug
(7) Three Gallons into Four Gallon (has Three)
(8) Solution: Two Gallons from Three Gallons into
Four Gallons
Three Gallon
Jug
Four Gallon Jug
(9) Transfer One
Gallon from Four
Gallon Jug to Three Gallon Jug
Three
Gallon
Jug
Four Gallon
Jug (empty)
(10) Solution: Transfer Two Gallons (to Fill) from
Four Gallon to Three
Gallon Jug
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