Algebra I Chapter 4 Section 1, 3, and 4 Quiz Review Guide
Algebra I Chapter 4 Section 1, 3, and 4 Quiz Review Guide Solutions
Homework problems and class examples are a good resource for studying. The following is a list of the major concepts that are being covered on the quiz and what the students should expect to do on the quiz for each concept.
Coordinate Plane:
• Identify the coordinates of a point
• Graph a point on the coordinate plane
• Identify the quadrant of a point
Midpoint Formula: [pic]
• Find the midpoint of two points
Relations
• Represent a relation as a …
o Set of ordered pairs
o Table
o Graph
o Mapping
• Find the Inverse of a relation
• Identify the Domain and Range
Find the solution set of an equation given…
• Replacement set
• Domain
• Solve for the dependent variable
Practice Problems
1) What quadrant are each of the point located in?
o (-5, 5): Quadrant II
o (13, 9): Quadrant I
o (3, 0): No Quadrant
o (0, -4) : No Quadrant
o (-5, 7): Quadrant II
o (3, -2): Quadrant IV
2) What is the midpoint of…
o (-5, 5) and (13, 9): Midpoint = (4, 7)
o (3, -4) and (-7, 6): Midpoint = (-2, 1)
3) Starting at the point (2, -3). If you go up 3, left 5, down 7 and right 2, then what point do you end up at?
Start (2, -3); Up 3 = (2, 0); Left 5 = (-3, 0); Down 7 (-3, -7); Right 2 (-1, -7)
Solution: (-1, -7)
4) For the given relation (set of ordered pairs): {(0,3), (-2,4), (1, 5), (4, -3), (-1, -3)}
o Write the relation as TABLE.
|X |Y |
|0 |3 |
|-2 |4 |
|1 |5 |
|4 |-3 |
|-1 |-3 |
o Write the relation as a MAPPING.
o What is the DOMAIN and RANGE of the relation?
Domain = {0, -2, 1, 4, -1} Range = {3, 4, 5, -3}
o What is the INVERSE of the relation?
Inverse = {(3,0), (4, -2), (5, 1), (-3, 4), (-3, -1)}
5) Find the SOLUTION SET given the replacement set {(0, -2), (-1, 4), (3, 2), (1, 1), (2, 4)} and equation y = 3x – 2.
|X |Y |Equation y = 3x -2 |Solution? |
|0 |-2 |-2 = 3(0) – 2 |Yes |
|-1 |4 |4 = 3(-1) – 2 |No |
|3 |2 |2 = 3(3) – 2 |No |
|1 |1 |1 = 3(1) – 2 |Yes |
|2 |4 |4 = 3(2) – 2 |Yes |
o Write the SOLUTION SET from as a TABLE.
|X |Y |
|0 |-2 |
|1 |1 |
|2 |4 |
o Write the SOLUTION SET from as a MAPPING.
[pic]
o Write the INVERSE of the solution set as ordered pairs.
Inverse of Solution Set = {(-2, 0), (1, 1), (4, 2)}
6) Solve the equation 4x + 2y = 8 for the given domain = {-3, -1, 0, 2, 4}.
|X |4x + 2y = 8 or y = 4 – 2x |Y |
|-3 |4 – 2(-3) |10 |
|-1 |4 – 2(-1) |6 |
|0 |4 – 2(0) |-2 |
|2 |4 – 2(2) |2 |
|4 |4 – 2(4) |0 |
o Write the SOLUTION SET from as a set as ordered pairs.
Solution Set: (-3, 10), (-1, 6), (0, 4), (2, 0), (4, -4)
o Write the INVERSE of the solution set as TABLE.
|X |Y |
|10 |-3 |
|6 |-1 |
|4 |0 |
|0 |2 |
|-4 |4 |
o Write the INVERSE of the solution set as MAPPING.
[pic]
-----------------------
3
4
5
-3
0
-2
1
4
-1
Y
X
-2
1
4
0
1
2
Y
X
-3
1
0
2
4
10
6
4
0
-4
Y
X
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