6%2D4 Elimination Using Multiplication

[Pages:38]6-4 Elimination Using Multiplication

Use elimination to solve each system of equations. 2x ? y = 4

7x + 3y = 27 62/87,21 Notice that if you multiply the first equation by 3, the coefficients of the y ?terms are additive inverses.

Now, substitute 3 for x in either equation to find y .

The solution is (3, 2).

2x + 7y = 1 x + 5y = 2 62/87,21 Notice that if you multiply the second equation by ?2, the coefficients of the x?terms are additive inverses.

Now, substitute 1 for y in either equation to find x.

The solution is (?3, 1).

eSolut4ioxns+M2aynu=al?- 1P4owered by Cognero 5x + 3y = ?17

62/87,21

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6-4 E limination Using Multiplication The solution is (?3, 1).

4x + 2y = ?14 5x + 3y = ?17 62/87,21 Notice that if you multiply the first equation by 3 and the second equation by ?2, the coefficients of the y ?terms are additive inverses.

Now, substitute ?4 for x in either equation to find y .

The solution is (?4, 1).

9a ? 2b = ?8 ?7a + 3b = 12 62/87,21 Notice that if you multiply the first equation by 3 and the second equation by 2, the coefficients of the y ?terms are additive inverses.

Now, substitute 0 for a in either equation to find b.

The solution is (0, 4).

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