Class- X Mathematics-Basic (241) Marking Scheme SQP-2020-21 ... - Edufever
Class- X
Mathematics-Basic (241)
Marking Scheme SQP-2020-21
Max. Marks: 80
Duration:3hrs
1
1
156 = 22 x 3 x 13
2
Quadratic polynomial is given by x2 - (a +b) x +ab
x2 -2x -8
1
3
HCF X LCM =product of two numbers
?
96 ? 404
???(96,404)
LCM (96,404) =
= 96 ? 404
4
?
LCM = 9696
OR
Every composite number can be expressed (factorized) as a product
of primes, and this factorization is unique, apart from the order in
which the factors occur.
4
1
x ¨C 2y =0
3x + 4y -20 =0
1
3
¡Ù
?2
4
?1
?
?1
As, ?2 ¡Ù ?2 is one condition for consistency.
Therefore, the pair of equations is consistent.
5
6
1
?
1
? = 60¡ã
?
Area of sector =360¡ã ¦°r2
60¡ã
A = 360¡ã X
1
A=6X
22
7
22
7
X (6)2 cm2
?
X36 cm2
= 18.86cm2
?
OR
Another methodHorse can graze in the field which is a circle of radius 28 cm.
So, required perimeter = 2¦°r= 2.¦°(28) cm
=2 x
22
7
X (28)cm
?
= 176 cm
7
?
By converse of Thale¡¯s theorem DE II BC
¨NADE = ¨NABC = 70¡ã
Given ¨NBAC = 50¡ã
¨NABC + ¨NBAC +¨NBCA =180¡ã (Angle sum prop of triangles)
700 + 500 + ¨NBCA = 180¡ã
¨NBCA = 180¡ã - 120¡ã = 60¡ã
?
?
OR
EC = AC ¨C AE = (7- 3.5) cm = 3.5 cm
??
2
?? 3.5
1
= 3 and ?? =3.5 = 1
??
??
??
So,
¡Ù
Hence, By converse of Thale¡¯s Theorem, DE is not Parallel to BC.
8
?
??
??
Length of the fence =
=
????? ????
????
??.5280
?? 24/?????
= 220 m
?
?
So, length of fence = Circumference of the field
¡à 220m= 2 ¦° r=2 X
So, r =
220 ? 7
2 ? 22
22
7
xr
m =35 m
?
9
??
Sol: tan 30 ¡ã =??
1/¡Ì3 =
?
??
8
AB = 8 / ¡Ì3 metres
Height from where it is broken is 8/¡Ì3 metres
?
10
Perimeter = Area
2¦°r = ¦°r2
r = 2 units
1
11
3 median = mode + 2 mean
1
12
8
1
13
?1
?2
?1
¡Ù ?2 is the condition for the given pair of equations to have unique
solution.
4
2
¡Ù
?
?
2
p ¡Ù4
?
Therefore, for all real values of p except 4, the given pair of equations
will have a unique solution.
OR
Here,
?1
?2
1
2
?1
?2
?1
?2
3
1
6
2
= =
=
1
2
¡Ù
?1
2
1
4
2
= =
and
?1
?2
=
5
7
5
7
?
?1
=
¡Ù
is the condition for which the given system of equations
?2
?2
will represent parallel lines.
14
So, the given system of linear equations will represent a pair of parallel
lines.
?
No. of red balls = 3, No.black balls =5
Total number of balls = 5 + 3 =8
?
3
8
?
Probability of red balls =
OR
Total no of possible outcomes = 6
There are 3 Prime numbers, 2,3,5.
3
1
So, Probability of getting a prime number is 6 = 2
?
?
15
?
?
tan 60¡ã = 15
¡Ì3 =
?
15
?
h = 15¡Ì3 m
16
1
1
17 i)
Ans : b)
Cloth material required = 2X S A of hemispherical dome
= 2 x 2¦° r2
1
= 2 x 2x
22
7
x (2.5)2 m2
= 78.57 m2
ii)
a) Volume of a cylindrical pillar = ¦° r2h
1
iii)
b) Lateral surface area = 2x 2¦°rh
1
=4
22
x
7
x 1.4 x 7 m2
= 123.2 m2
2
iv)
1
d) Volume of hemisphere =3 ¦° r3
2 22
7
=3
(3.5)3 m3
= 89.83 m3
v)
b)
2
Sum of the volumes of two hemispheres of radius 1cm each= 2 x 3 ¦°13
Volume of sphere of radius 2cm =
4
3
¦° 23
?
2
2 x 3 ¦° 13
So, required ratio is 4
¦° 23
3
=
1:8
?
18 i)
c) (0,0)
1
ii)
a) (4,6)
1
iii)
a) (6,5)
1
iv)
a) (16,0)
1
v)
b) (-12,6)
1
19 i)
c)
1
90¡ã
ii)
b) SAS
1
iii)
b) 4 : 9
1
iv)
d) Converse of Pythagoras theorem
1
v)
a) 48 cm2
1
d) parabola
1
ii)
a) 2
1
iii)
b) -1, 3
1
iv)
c) ? 2 ? 2? ? 3
1
v)
d) 0
1
20 i)
21
Let P(x,y) be the required point. Using section formula
? 1?2+?2?1 ?1?2+?2?1
,
}
?1+?2
?1+?2
3(8)+1(4)
x = 3+1
,
{
= (x, y)
y=
1
3(5)+1(?3)
3+1
x=7
y= 3
(7,3) is the required point
1
................
................
In order to avoid copyright disputes, this page is only a partial summary.
To fulfill the demand for quickly locating and searching documents.
It is intelligent file search solution for home and business.
Related download
- class 7 revision papers pdf with answers quilting academy
- marking scheme subject computer science class xii 2017 18 edufever
- class x mathematics basic 241 marking scheme sqp 2020 21 edufever
- physical education class xii marking scheme term 2 2021 2022
- marking scheme information technology subject code 402 paper code
- railway signals signs marks markers transportation markings a study
- gcse marking scheme mathsdiy
- courses of study and scheme of marking
- cbse class 9 english syllabus with marking scheme
- marking scheme 2021 2022 term ii home science 064 class xii q
Related searches
- class x ncert science heridity and evolution
- 2020 21 pell grant chart
- nyc doe 2020 21 calendar
- fafsa 2020 21 official site
- fafsa 2020 21 parent application
- fafsa application 2020 21 renewal
- fafsa application 2020 21 deadline california
- fafsa 2020 21 deadline
- fafsa 2020 21 log in
- fafsa application 2020 21 online
- fcps 2020 21 school calendar
- class 11 mathematics solutions ncert