Practice Worksheet for Significant Figures



Chp 3 Sig Fig, A/P, and % Error Review WS1. State the number of significant digits in each measurement.? 1)??? 280,400 m?4????????? 2)?? 2.84 km? 3?????????? ? 3)?? 5.029 m??4???????????4)?? 0.003068 m???????4?? 5)?? 4.6 x 105 m???2????? 6)?? 4.06 x 10-5 m???37)?? 750. m????3????????? 8)? 0.075 m????2???????????????????????? 9)?? 75,000 m 2 10)?? 75.00 m????4?? 11)? 75,000.0 m??6????? 12)? 0.0100200 cL 62. Round the following numbers: A) 1 B) 2 C) 3 D) 4 sig figs.21.860051 A) 20 B) 22 C) 21.9 D) 21.86375.9723 A) 400 B) 380 C) 376 D) 376.00.0480802744 A) 0.05 B) 0.048 C) 0.0481 D) 0.048083. Solve the following problems and report answers with appropriate number of significant digits.1)????? 6.201 cm + 7.4 cm?+?0.68 cm?+12.0 cm?=? 26.3 cm2)???? 1.6 km + 1.62 m +1200 cm?=?? 1203 m3)???? 8.264 g - 7.8 g?=??? 0.5 g4)???? 10.4168 m?-?6.0 m?=??4.4 m 5)???? 12.00 kg+15.001 kg=?? 27.00 kg6)???? 1.31 cm?x?2.3 cm?=?? 3.0 cm27)???? 5.7621 m?x?6.201 m?=? 35.73 m28)??? 20.2 cm / 7.4107 s?=?? 2.73 cm/s9)??? 40.002 g?/ 13.000005 g?= 3.07714. Express the left side in scientific notation and right side in standard notation. 123,876.3 1.238763 x 1058.45 X 107 84,500,0001,230,000 1.23 x 1066.74 X 103 67400.002380 2.380 x 10-35.767 X 10-6 0.0000057670.0000205 2.05 x 10-54.7 X 10-2 0.04715,009.22 1.500922 x 1049.7112 X 102 971.125. Solve the problems below: 1) (8.41 X 104) + (9.71 X 104) = 1.81 x 1052)(5.11e2) - (4.2e2) = 913) (2 X 107) (8 X 10-9) = 0.24) (4.11e-6) / (7.51e-4) = 5.47e-36. Are the following targets accurate, precise, both, or neither?P, not AA and PA, not P7. Draw a target that is: A. Accurate, but not preciseB. Precise, but not accurateSee above8. Find the percent error for the following problems:A student measured the mass of some sodium chloride for a lab. The lab called for 6.25 g (the accurate measurement), but the student measured 6.00 g instead. What is the percent error for this mass?(6.00 g – 6.25 g) / 6.25 = .0400 * 100 = 4.00%A lab group turned in their experiment and had measured the mass of their sample to be 3.15 g. The teacher had asked for them to make a sample of 3.10 g (the accurate value). What is their percent error?(3.15 g – 3.10 g) / 3.10 g = 0.0161 * 100 = 1.61%Students were measuring distances and found one to be 2.04 m. When they asked the teacher if their measurement was correct, the teacher said, “Actually, it is 2.16 m.” What is the percent error?(2.04 m - 2.16 m) / 2.16 m = .0556 * 100 = 5.56%A student measured a volume using a graduated cylinder. They read the volume to be 9.01 mL. The teacher read the volume and said the accurate value is 8.97 mL. What is their percent error?(9.01 mL – 8.97 mL) / 8.97 mL = 0.00446 * 100 = 0.446% ................
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