Converting the Form Asinx + Bcosx to the Form Ksin(y + x)
Differential Equations Equation of Motion
Converting the Form A sin x + B cos x to the Form K sin(x + )
Given the expression A sin x + B cos x, we are going to change it to the expression K sin(x + ).
Find the value of K and .
K = A2 + B2
A sin x + B cos x =
A2 + B2
Asin x + A2 + B2
Bcos x A2 + B2
sin = B A2 + B2
cos = A . A2 + B2
A sin x + B cos x = K (sin x cos + cos x sin ) = K sin(x+ ).
Example: convert 5sin x - 7cos x
K = 52 + (-7)2 = 25+ 49 = 74 = 8.6
sin = - 7 = -54.5o 8.6
cos = 5 = 54.5o 8.6
Since the sine is negative and the cosine is positive, must be in quadrant IV, and = -54.5o. The final equation is:
5sin x - 7cos x = 8.6sin(x - 54.5)
Department of Mathematics, Sinclair Community College, Dayton, OH
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When the equation of motion x(t) = c1 cos t + c2 sin t is converted to
x(t) = A sin (t + ), where A =
c2 1
+c22
,
A
is
the
amplitude
of
free
vibrations
( is the phase angle).
Example: 2sin x + 5cos x is plotted. What is the amplitude of the graph?
K = 22 +52 = 29 = 5.4 2sin x + 5cos x = 5.4sin (x + )
Therefore the amplitude is 5.4.
Exercises: Convert: 1. 3 sin x - 3 cos x 2. 6 sin x + 8 cos x 3. 2 sin x + cos x 4. sin x + cos x 5. 3 sin x - 3 cos x
Answers: 1. 2 3 sin (x - 30) 2. 10 sin (x + 53.1) 3. 5 sin (x + 26.6) 4. 2 sin (x + 45) 5. 2 3 sin (x - 60)
Department of Mathematics, Sinclair Community College, Dayton, OH
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