Lesson Plan Template - Hollywood High School



Wendy Perez

Period 2 Ap Calculus

Student Made Calculus Lesson Plan

Lesson Objectives:

PreREQUISITE KNOWLEDGE (10 mins):

Answers

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|1) [pic][pic] |

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|2) [pic][pic] |

|[pic][pic]  [pic][pic] [pic] |

|[pic] |

|3)       [pic][pic] |

|  [pic][pic]        [pic][pic] |

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|4) [pic][pic] |

| [pic] [pic] |

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|5) |

|[pic] |

Lesson Plan:

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|Introduction (5mins): |

|Standard: The mathematical process of finding the rate at which a trigonometric function changes with respect to a variable--the derivative of the |

|trigonometric function. Commonplace trigonometric functions include sin(x), cos(x) and tan(x). Knowledge of differentiation from first principles is |

|required, along with competence in the use of trigonometric identities and limits. All functions involve the arbitrary variable x, with all |

|differentiation performed with respect to x. Knowing the deriatives of sin(x) and cos(x), one can easily compute the derivatives of the other circular |

|trigonometric functions because they can all be expressed in terms of sine or cosine; the quotient rule is then implemented to differentiate this |

|expression. Proofs of the derivatives of sin(x) and cos(x) are given in the proofs section; the results are quoted in order to give proofs of the |

|derivatives of the other circular trigonometric functions |

|LESSON (15 mins): |

|Okay, now that we’ve gotten this set of limit examples out of the way let’s get back to the main point of this section, differentiating trig functions. |

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|We’ll start with finding the derivative of the sine function.  To do this we will need to use the definition of the derivative.  It’s been a while since|

|we’ve had to use this, but sometimes there just isn’t anything we can do about it.  Here is the definition of the derivative for the sine function. |

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|[pic][pic] |

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|Since we can’t just  plug in [pic][pic] to evaluate the limit we will need to use the following trig formula on the first sine in the numerator.  |

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|[pic][pic] |

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|Doing this gives us, |

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|[pic][pic] |

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|As you can see upon using the trig formula we can combine the first and third term and then factor a sine out of that.  We can then break up the |

|fraction into two pieces, both of which can be dealt with separately. |

|Now, both of the limits here are limits as h approaches zero.  In the first limit we have a sin(x) and in the second limit we have a cos(x).  Both of |

|these are only functions of x only and as h moves in towards zero this has no affect on the value of x.  Therefore, as far as the limits are concerned, |

|these two functions are constants and can be factored out of their respective limits.  Doing this gives, |

|[pic][pic] |

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|At this point all we need to do is use the limits in the fact above to finish out this problem. |

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|[pic][pic] |

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|Differentiating cosine is done in a similar fashion.  It will require a different trig formula, but other than that is an almost identical proof.  The |

|details will be left to you.  When done with the proof you should get, |

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|[pic][pic] |

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|With these two out of the way the remaining four are fairly simple to get.  All the remaining four trig functions can be defined in terms of sine and |

|cosine and these definitions, along with appropriate derivative rules, can be used to get their derivatives. |

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|Let’s take a look at tangent.  Tangent is defined as, |

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|[pic][pic] |

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|Now that we have the derivatives of sine and cosine all that we need to do is use the quotient rule on this.  Let’s do that. |

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|[pic][pic][pic] |

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|Now, recall that [pic][pic] and if we also recall the definition of secant in terms of cosine we arrive at, |

|[pic][pic] |

|The remaining three trig functions are also quotients involving sine and/or cosine and so can be differentiated in a similar manner.  We’ll leave the |

|details to you.  Here are the derivatives of all six of the trig functions. |

|Derivatives of the six trig functions: |

|[pic] |

|Conclusion: PRACTICE (10 MINS): |

|Differentiate each of the following functions. |

|(a) [pic][pic] |

|There really isn’t a whole lot to this problem.  We’ll just differentiate each term using the formulas from above. |

|                                        [pic][pic] |

|(b) [pic] |

|In this part we will need to use the product rule on the second term and note that we really will need the product rule here.  There is no other way to |

|do this derivative unlike what we saw when we first looked at the product rule.  When we first looked at the product rule the only functions we knew how|

|to differentiate were polynomials and in those cases all we really needed to do was multiply them out and we could take the derivative without the |

|product rule.  We are now getting into the point where we will be forced to do the product rule at times regardless of whether or not we want to. |

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|We will also need to be careful with the minus sign in front of the second term and make sure that it gets dealt with properly.  There are two ways to |

|deal with this.  One way it to make sure that you use a set of parenthesis as follows, |

|                             [pic][pic] |

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|Because the second term is being subtracted off of the first term then the whole derivative of the second term must also be subtracted off of the |

|derivative of the first term.  The parenthesis make this idea clear. |

|A potentially easier way to do this is to think of the minus sign as part of the first function in the product.  Or, in other words the two functions in|

|the product, using this idea, are \\\[pic][pic] and [pic][pic].  Doing this gives, |

|      [pic][pic][pic] |

|So, regardless of how you approach this problem you will get the same derivative. |

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|(c) [pic][pic] |

|As with the previous part we’ll need to use the product rule on the first term.  We will also think of the 5 as part of the first function in the |

|product to make sure we deal with it correctly.  Alternatively, you could make use of a set of parenthesis to make sure the 5 gets dealt with properly. |

|Either way will work, but we’ll stick with thinking of the 5 as part of the first term in the product.  Here’s the derivative of this function. |

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|[pic] |

|(d)  [pic][pic] |

|In this part we’ll need to use the quotient rule to take the derivative. |

|                                  [pic][pic] |

|Be careful with the signs when differentiating the denominator.  The negative sign we get from differentiating the cosine will cancel against the |

|negative sign that is already there. |

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|This appears to be done, but there is actually a fair amount of simplification that can yet be done.  To do this we need to factor out a “-2” from the |

|last two terms in the numerator and the make use of the fact that [pic][pic]. |

|[pic][pic] |

ENRICHMENT ACTIVITIES (10 mins):

|(1) Differentiation |

|Trig derivatives |

|Derive the following trig functions. For credit, you must show all steps and explain the mathematical purpose of each step. |

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|[pic] [pic] |

|[pic] [pic] |

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|Hints: |

|Rewrite the trig function using only sin and cos |

|Use the quotient rule to find the derivative |

|Use various trig relationships to rewrite the derivative without sin or cos |

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|(2) Mathematical Muscle-building: |

|Inverse Trigonometric Functions |

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|d/dx (sin-1u) = (1-u2)-1/2 (du/dx) |

|and |

|d/dx (tan-1u) = (1+u2)-1 (du/dx) |

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|(1) Find y' when |

|(a) y = sin-1(x2) |

|(b) y = sin-1(ex) |

|(c) y = sin-1[ e sin-1x] |

|(d) [tan-1(x)](1+x2) |

|(2) Find y' by implicit differentiation from (tan-1y)(x2+1) = 10. |

|(3) Without trying to solve for y', implicitly differentiate sin-1(exy) = 5 |

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Assessment

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|Calculate dy/dx if or find the derivatives of the following functions: |

|1. y = sin(3x2[pic]1) 2. y = cosec x 3. f(x) = tan(x2[pic]1) |

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|4. g(x) = cosec(e3x) 5. h(x) = e[pic]xsin(2x) 6. s(x) = sin(x2) |

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|7. r(x) = sin2x 8. y = x sin x 9. y= x2+x/ sin x |

Resources

|Videos that tutor the topic |

|Hippocampus Video Trigonometric Functions it talks about the proofs of the sin and cos rules and the site also shows how to derive all of the trig |

|functions. |

|Calculus 3.o8d video Derive Trig Functions has examples of derivative problems involving trig functions. |

|AP Calculus Exam Prep video Second Derivatives teaches how to find and evaluate the second derivative of sine squared function. |

|Bright Storm video Derivatives defines how the derivative is a function which is derived from another function. |

|Fun things that tutor the topic |

|Calculus Matching game Studystack it gives you the function and the player is suppose to match the derivative. |

|Songs and poems on WIld Storm that reviews ideas and mnemonic devices for remembering rules. |

|Multiple applets Differentiation that are games and puzzles that involve solving derivatives. |

|Websites that tutor the topic |

|In the calculusapplet website on Derivative Functions defines the derivative point and how it tells us the value of the derivative for any point on the |

|original function. |

|In the calculusapplets website on Second Derivatives explains taking the derivative of a function to another function. |

|In visual calculus on Trig Derivatives teaches the objectives which is to find the derivatives of the six trigonometric functions by using the product |

|and quotient rules. |

HOMEWORK

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(Key Knowledge and Skills students should achieve in the lesson)

1. Finding the derivatives of six trigonometric functions

2. Derive the formulas for the derivatives of the trigonometric functions

3. Diffrentiate functions which involve trigonometric functions

4. Can use the product and Quotient rules when using the trigonometric functions

(What should a student know beforehand?- Warm-up related?)

Evaluate each of the following limits

1) [pic][pic]    2) [pic][pic]    3) [pic][pic]    4) [pic][pic]  5) [pic]\[pic] 

Topic: Trig Derivative Lesson # 25

Textbook: Read pgs 213-218; Do 2, 9, 10, 13, 17,

MMM Worksheet: Differentiation of Trig Functions

Other Worksheet: Vitutor worksheet: Derivatives

MathExcel worksheet: Derivatives of Trig Functions

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