π 3π nπ 2 f π f 3π 2 π nπ, 3π nπ, n - WebAssign
For the tangent line to be horizontal, f (x) = 0. f (x) = 2sinx + sin2x
f (x) = 2cosx+2sinx cosx = 0 2cosx(1 + sinx) = 0 cosx = 0
or
sinx
=
-1,
so
x
=
2
+2n
or
3 2
+2n,
where
n
is
any
integer.
Now
f
2
= 3 and f
3 2
= -1, so the points on the curve with a horizontal
tangent are
2
+2n,
3
and
3 2
+2n
,
-1
,
where
n
is
any
integer.
................
................
In order to avoid copyright disputes, this page is only a partial summary.
To fulfill the demand for quickly locating and searching documents.
It is intelligent file search solution for home and business.
Related download
- 3 2 provingidentities all in one high school
- honors precalculus prove the following identities
- math 2250 exam 2 solutions
- assignment 4 university of california berkeley
- trigonometry identities i introduction math plane
- useful trigonometric identities
- π 3π nπ 2 f π f 3π 2 π nπ 3π nπ n webassign
- step support programme step 2 trigonometry questions solutions maths
- mas113 calculus ii tutorial 11 solutions section 2 6 ode book
- partial solutions for section 3 university of colorado boulder