MatLab Programming – Lesson 1 (a
will ever be different from zero. This gives us a system of two equations, the solutions of which will give all possible locations for the extreme values of f on the boundary. gradg=jacobian(g,[x,y,z]) gradcross=cross(gradf,gradg); lagr=gradcross(3) [xboundcrit,yboundcrit]=solve(g-4,lagr) MATLAB appears to have found a constrained critical … ................
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