Surface area and surface integrals. (Sect. 16.5) Review ...
Surface area and surface integrals. (Sect. 16.5)
Review: Arc length and line integrals. Review: Double integral of a scalar function. Explicit, implicit, parametric equations of surfaces. The area of a surface in space.
The surface is given in parametric form. The surface is given in explicit form.
Review: Arc length and line integrals
The integral of a function f : [a, b] R is
b
n
a
f (x) dx = lim
n
f (xi) x.
i =0
The arc length of a curve r : [t0, t1] R3 in space is
t1
st1,t0 = |r (t)| dt.
t0
The integral of a function f : R3 R along a curve
t1
r : [t0, t1] R3 is f ds = f r(t) |r (t)| dt.
C
t0
The circulation of a function F : R3 R3 along a curve
t1
r : [t0, t1] R3 is F ? u ds = F r(t) ? r (t) dt.
C
t0
The flux of a function F : {z = 0} R3 {z = 0} R3 along
a loop r : [t0, t1] {z = 0} R3 is F = F ? n ds.
C
Surface area and surface integrals. (Sect. 16.5)
Review: Arc length and line integrals. Review: Double integral of a scalar function. Explicit, implicit, parametric equations of surfaces. The area of a surface in space.
The surface is given in parametric form. The surface is given in explicit form.
Review: Double integral of a scalar function
The double integral of a function f : R R2 R on a region R R2, which is the volume under the graph of f and above
the z = 0 plane, and is given by
nn
R
f
dA
=
lim
n
i =0
j =0
f
(xi, yj) x
y .
The area of a flat surface R R2 is the particular case f = 1, that is, A(R) = dA.
R
We will show how to compute: The area of a non-flat surface in space. (Today.) The integral of a scalar function f on a surface is space. The flux of a vector-valued function F on a surface in space.
Surface area and surface integrals. (Sect. 16.5)
Review: Arc length and line integrals. Review: Double integral of a scalar function. Explicit, implicit, parametric equations of surfaces. The area of a surface in space.
The surface is given in parametric form. The surface is given in explicit form.
Explicit, implicit, parametric equations of surfaces
Review: Curves on R2 can be defined in:
Explicit form, y = f (x); Implicit form, F (x, y ) = 0; Parametric form, r(t) = x(t), y (t) . The vector r (t) = x (t), y (t) is tangent to the curve.
Review: Surfaces in R3 can be defined in:
Explicit form, z = f (x, y ); Implicit form, F (x, y , z) = 0; Parametric form, r(u, v ) = x(u, v ), y (u, v ), z(u, v ) . Two vectors tangent to the surface are
ur(u, v ) = ux(u, v ), uy (u, v ), uz(u, v ) , v r(u, v ) = v x(u, v ), v y (u, v ), v z(u, v ) .
Explicit, implicit, parametric equations of surfaces
Example
Find a parametric expression for the cone z = tangent vectors.
x2 + y 2, and two
Solution: Use cylindrical coordinates: x = r cos(), y = r sin(), z = z. Parameters of the surface: u = r , v = . Then
x(r , ) = r cos(), y (r , ) = r sin(), z(r , ) = r . Using vector notation, a parametric equation of the cone is
r(r , ) = r cos(), r sin(), r .
Two tangent vectors to the cone are r r and r, r r = cos(), sin(), 1 , r = -r sin(), r cos(), 0 .
Explicit, implicit, parametric equations of surfaces
Example
Find a parametric expression for the sphere x2 + y 2 + z2 = R2, and two tangent vectors. Solution: Use spherical coordinates: x = cos() sin(), y = sin() sin(), z = cos(). Parameters of the surface: u = , v = .
x = R cos() sin(), y = R sin() sin(), z = R cos(). Using vector notation, a parametric equation of the cone is
r(, ) = R cos() sin(), sin() sin(), cos() .
Two tangent vectors to the paraboloid are r and r, r = R - sin() sin(), cos() sin(), 0 ,
r = R cos() cos(), sin() cos(), - sin() .
Surface area and surface integrals. (Sect. 16.5)
Review: Arc length and line integrals. Review: Double integral of a scalar function. Explicit, implicit, parametric equations of surfaces. The area of a surface in space.
The surface is given in parametric form. The surface is given in explicit form.
The area of a surface in parametric form
Theorem
Given a smooth surface S with parametric equation
r(u, v ) = x(u, v ), y (u, v ), z(u, v ) for u [u0, u1] and v [v0, v1]
is given by
u1 v1
A(S) =
|ur ? v r| dv du.
u0 v0
z S = { r ( u, v ) }
u= 0 v= 0
du r y
x
dv r
Remark: The function
d = |ur ? v r| dv du.
represents the area of a small region on the surface. This is the generalization to surfaces of the arc-length formula for the length of a curve.
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