Hints and Solutions to Selected Problems

10a. Remember, velocity is the rate of change (derivative) of position. b. And acceleration is the rate of change of velocity (second derivative of position). c. v = 3t2 – 3 = 0 when t = 1. a(1) = 6 m/s2. 11. Multiply by g(x) to clear fraction: Solve for q': This is usually written: Derivative Techniques – 2. 4 – 8. ................
................