Multiple Choice – Only one answer is correct

Ag+ + Cl− → AgCl Calculate mole of NaCl: 1 L × 0.1 M = 0.1 mol of NaCl and NaCl gives us only one Cl− per NaCl. But for the CaCl2, a “buy 1 get 2” substance, for 0.1 mol of CaCl2 we get 0.2 mole of Cl−. Thus we have a total of 0.3 mol of Cl− which will require 0.3 mol … ................
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