Efficiency of a Light Bulb
E (joules) = (watts) (time in seconds) Watt = (current in amps) (voltage) Joule = watt -second. Calculate the energy released as heat (Q): Q = (m) (c ) (change t) Q (released from light bulb in joules) = (mass of air in g) (specific heat air in Joules) (change t in oC) Specific heat air = 1.012 joules / gram - oC ................
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