The Pearson correlation - Testing for significance - ConsultGLP
[Pages:1]The Pearson correlation ? Testing its significance
The correlation coefficient is much used in sciences where relationships between variables subject to many influence factors are being studied. As r2 of 0.5 might turn out to be highly significant in the case of the epidemiology of some disease, for the laboratory analytical chemist, the calibration model is usually a very good description of the relationship between variables (e.g. concentrations of standards and instrumental responses).
Hence, in general, when we have obtained the linear correlation coefficient, r
from two variables, we must then ask if this correlation is significant or not.
We can conduct a significance testing with the null hypothesis Ho being no
relationship between the variables, i.e. r = 0 and the alternative hypothesis H1 being r 0. We will use an alpha level of 0.05 and a t-test statistic
formula as below to test whether our results are significantly different from zero 0;
where
r n-2 t=
1- r2
r is the Pearson correlation coefficient for the sample, and n is the sample size (i.e. the number of data sets)
By relooking at the r value of the example mentioned in last blog on "The Pearson correlation coefficient", we have r = 0.999 and n = 6 and hence,
0.999 6 - 2 1.998
t =
=
= 44.7
1 - 0.9992 0.045
According to the t-table, the critical value for a two-tailed t -test with 4 degrees of freedom at = 0.05 is 2.777. As our computed value t = 44.7 is
very much larger than the critical value 2.777, we will reject the null hypothesis which states that the standard concentrations and the instrument intensities are unrelated. Similarly, the p-value calculated is 1.5x10-6 which
is less than 0.05, indicating similar conclusion. In other words, the r-value
and hence the correlation between these two variables were highly significant.
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