Action Rule Discovery Example - University of North ...
Action Rule Discovery Example
Assume that C is a decision attribute in Table 1 from the previous problem (in Decision rules - LERS (certain and possible rules) lecture). Also, assume that G is a stable attribute, and {A, F} are flexible. Find all action rules re-classifying objects in Table 1 from the class C(c2) to C(c1).
To compose the action rules, we will use the rules discovered in the previous problem (in Decision rules - LERS (certain and possible rules) lecture). We will only use the certain rules. They were:
Certain Rules: (from marked)
a2 ( c2
f1 ( c2
g3 ( c2
Certain Rules: (from marked in Second Loop)
a1 ^ g2 ( c1
f2 ^ g1 ( c1
Since we want to reclassify objects from the class c2 to c1, then we look for rules,
which have c2 on the right hand side and compare them to rules, which have c1 on the right hand side. Next, we look on the left hand side, and see if the two rules have a common attribute, for example a. So, we write those two rules below, and yes, we see that they have a common attribute a. In the first rule, the value of a is 2, in the second rule, the value of a is 1. So, if we want to re-classify the objects from the first rule (class c2) to the second rule (class c1), then we need to take the action of changing the value of a from 2 to 1.
From:
a2 ( c2
a1 ^ g2 ( c1
we compose the following action rule:
(a, 2(1) ^ (g = 2) ( (c, 2(1)
From:
f1 ( c2
f2 ^ g1 ( c1
we compose the following action rule:
(f, 1(2) ^ (g = 1) ( (c, 2(1)
• Note: G is stable attribute, therefore its value cannot be changed. For example, if G is date of birth, then its value is set to a particular date, which cannot be changed. In our case (first action rule above), the value of g is set to 2, so we write (g = 2). In other words, the objects (x) for which we will change the value of (a, 2(1) will need to always have g = 2 for the action rule to be applicable.
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