Chapter 12 (p - Ryono
Chapter 12 (p.377) #37,38
37. [pic] Watch out for weight vs mass!
Force Equation: [pic]
Torque Equation (w.r.t. A): [pic]
[pic] [pic] [pic]
(Just another teeter-totter problem, right?) plugging back… [pic]
38. [pic] [pic]
I thought this one was tricky. It looked easy at first when I considered both rods as one.
Then I saw only four forces NA + NB = 2(26) and by symmetry NA = NB, so NA = 26N.
However, to find the tension, we need to shift to just one rod (say the right side & pt B),
but now we have to consider the contact or hinge force of the left rod on our right one!
So I drew in the hinge force components, Px and Py as shown above, but wait!
When I wrote my force equations, I made an error.
Force Equations: [pic] (That one’s okay)
But Py + NB = 26N (is wrong… Just above we got NB = 26N, so Py = 0N
So [pic] is okay. (The Py = 0N is similar to a frictionless wall problem.)
Torque Equation (wrt pt B): ?
Here we’ll have to do some geometry or right triangle trig: .65
[pic] (Ah, the old 5-12-13 rt[pic])
Anyway, back to our torque equation… [pic] .60 [pic]
[pic] and since Px = T, we get:
[pic]
-----------------------
B
B
Py
Px
[pic]
T [pic]
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