EDUCATIONAL EVALUATION REPORT
The remaining 20 letters can be arranged in any sequence (there are 20! ways to arrange the other 20 letters in the remaining 20 spots). Therefore, there are 21x20! = 21! ways to get Hamlet. There are 26 letters to fill 26 spots, so there are 26! total arrangements of the letters. (P(getting Hamlet) = very small! ................
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