EGR 511 - California State Polytechnic University, Pomona

The solution to the above equation is y = Acos x + Bsin x + 1. From the boundary conditions y(0) = 0 and y((/2) = 0 we have ... ( 1 ( = Solving for dx gives. dx = dy (6.3-4) Equation (6.3-4) can be integrated parametrically by the following procedure: ... [Notice that the equation may be taken in the form y = x + cx(1 ( x), where c is to be ... ................
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