Bài2(trang168SGKĐạisố11):Giảicácbấtphươngtrìnhsau

Gii b?i tp To?n 11 Gii t?ch: o h?m ca h?m s lng gi?c B?i 1 (trang 168 SGK i s 11): T?m o h?m ca c?c h?m s sau: Li gii:

B?i 2 (trang 168 SGK i s 11): Gii c?c bt phng tr?nh sau: Li gii:

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B?i 3 (trang 169 SGK i s 11): T?m o h?m ca c?c h?m s sau: Li gii:

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B?i 4 (trang 169 SGK i s 11): T?m o h?m ca c?c h?m s sau:

Li gii: a.y'=[(9 - 2x)(2x3 ? 9x2 + 1)]' = (9 ? 2x )' (2x3 ? 9x2 + 1) + (9 ? 2x)(2x3 ? 9x2 + 1)' = - 2(2x3 ? 9x2 + 1) + (9 ? 2x)(6x2 ? 18x) = -16x3 ? 108x2 ? 162x ? 2

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B?i 5 (trang 169 sgk i S 11): T?nh ... Li gii:

B?i 6 (trang 169 SGK i s 11): Chng minh rng c?c h?m s sau c? o h?m kh?ng ph thuc x:

Li gii:

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B?i 7 (trang 169 SGK i s 11 ): Gii phng tr?nh f'(x) = 0, bit rng: Li gii:

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