Problems. Your approach may be di erent but may still be ...
2x 2 2sin 4 2 cos 2x 2 = sin(2x)sin( x) sin(2x)cosx = sin(2x)sinx sin(2x)cosx = sinx cosx = tanx = RHS. h. sinx 1 cosx = (cscx)(1 + cosx) Ans: LHS = sinx 1 cosx = (sinx)(1 + cosx) (1 cosx)(1 + cosx) = sinx(1 + cosx) 1 cos2 x = sinx(1 + cosx) sin2 x = 1 + cosx sinx = (1 + cosx) 1 sinx = (1 + cosx)cscx = RHS. i. sin2x cotx = 1 cos2x Ans: LHS ... ................
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