Document2 - Arkansas Tech University

sin x —1 sm x smx smx o 4sinxcosx — 2-6 sin x — cosx + — 0 2sinx(2cosx v6(2cosx 0 (2 cos x — sm x 2cosx— — O cos x Il;r The solutions are 6 4 2sinx— — O 4 sm x 3m 11m 6 2sin2 x +1 2sm x—3smx+1 (2 sin x — x — 1) 3 smx 0 0 0 2' sin x — 1 sm x 6 2sinx —1 0 sm x 6 6 m The solutions are 6 ................
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