Name:_______________________
Name:_______________________
Covers Chapter 6 |CSCI 1301 Introduction to Programming
Armstrong Atlantic State University
Instructor: Y. Daniel Liang | |
(50 minutes)
Part I: Multiple Choice Questions: (1 pts each)
1. Suppose array a is int[] a = {1, 2, 3}, what is a[0] - a[2]?
a. 1
b. 2
c. 3
d. None of the above
2. An array reference variable can be used in which of the following ways?
a. As a local variable
b. As a parameter of a method
c. As a return value of a method
d. All of the above
3. Which of the following are valid array declarations?
a. char[] charArray = new char[26];
b. int[] words = new words[10];
c. char[] charArray = "Computer Science";
d. double[3] nums = {3.5, 35.1, 32.0};
e. None of the above
4. Consider the following code fragment:
int[] list = new int[10];
for (int i = 0; i = 0; i--)
System.out.print(list2[i] + " ");
}
}
a. 1 2 3
b. 3 2 1
c. 0 1 2
d. 2 1 0
e. 0 1 3.
10. Analyze the following code:
public class Test {
public static void main(String[] args) {
int[] x = {0, 1, 2, 3, 4, 5};
xMethod(x, 5);
}
public static void xMethod(int[] x, int length) {
for (int i = 0; i < length; i++)
System.out.print(" " + x[i]);
}
}
a. The program displays 0 1 2 3 4.
b. The program displays 0 1 2 3 4 and then raises a runtime exception.
c. The program displays 0 1 2 3 4 5.
d. The program displays 0 1 2 3 4 5 and then raises a runtime exception.
11. Analyze the following code:
public class Test {
public static void main(String[] args) {
int[] x = new int[5];
for (int i = 0; i < x.length; i++)
x[i] = i;
System.out.println(x[i]);
}
}
a. The program displays 0 1 2 3 4.
b. The program displays 4.
c. The program has a runtime error because the last statement in the main method causes ArrayIndexOutOfBounds exception.
d. The program has syntax error because i is not defined in the last statement in the main method.
12. Assume double[] scores = {1, 2, 3, 4, 5}, what value does java.util.Arrays.binarySearch(scores, 3.5) return?
a. 0
b. -4
c. 3
d. -3
e. 4
Part II: Show the printout of the following code:
a. (1 pts)
public class Test {
public static void main(String[] args) {
int[] a = {1, 2};
swap(a[0], a[1]);
System.out.println("a[0] = " + a[0] + " a[1] = " + a[1]);
}
public static void swap(int n1, int n2) {
int temp = n1;
n1 = n2;
n2 = temp;
}
}
b. (1 pts)
public class Test {
public static void main(String[] args) {
int[] a = {1, 2};
swap(a);
System.out.println("a[0] = " + a[0] + " a[1] = " + a[1]);
}
public static void swap(int[] a) {
int temp = a[0];
a[0] = a[1];
a[1] = temp;
}
}
c. (4 pts) Given the following program, show the values of the array in the following figure:
public class Test {
public static void main(String[] args) {
int[] values = new int[5];
for (int i = 1; i < 5; i++) {
values[i] = i;
}
values[0] = values[1] + values[4];
}
}
[pic]
d. (1 pts) Show the printout of the following program:
public class Test {
public static void main(String[] args) {
double[] numbers = {1, 4.3, 5.55, 3.4};
double[] x = numbers;
numbers[0] = 300;
System.out.println(x[0]);
}
}
Part III:
a. (3 pts): Suppose a matrix is created as follows: int[][] matrix = new int[4][5].
1. Write a statement without using a loop to add its second column.
2. Write a loop to add its second column.
b. (3 pts): Write a method that computes the average of the values in an array of doubles. The header of the method is as follows:
public static double average(double[] x)
c. (3 pts) Write a method that returns the index of the smallest element in an array of integers. If there are more than one such element, return the smallest index.
public static int indexOfSmallestElement(int[] list)
d. (7 pts): Write a method that returns a new array with no duplicates. The header of the method is as follows:
public static int[] removeDuplicate(int[] x)
For example, if x is {1, 3, 1, 2, 3, 5}, removeDuplicate(x) returns a new array {1, 3, 2, 5}
(Hint: To be given in the class)
Key
Part I: Multiple Choice Questions: (1 pts each)
1. d
2. d
3. a
4. d
5. d
6. a
7. a
8. a
9. d
10. a
11. d
12. b
Part II. (3 pts) Find and fix all errors in the following program:
(A)
public class Test
{
public static void main(String[] args)
{
double[] list = {3, 4, 5, 6.3};
xMethod(list);
}
public static double xMethod(double[] list)
{
for (int i=0; i low should be high >= low
Part III: Show the printout of the following code:
a. (2 pts each)
public class Test
{
public static void main(String[] args)
{
int[] a = {1, 2};
swap(a[0], a[1]);
System.out.println("a[0] = " + a[0] + " a[1] = " + a[1]);
}
public static void swap(int n1, int n2)
{
int temp = n1;
n1 = n2;
n2 = temp;
}
}
a[0] = 1 a[1] = 2
b. (2 pts each)
public class Test
{
public static void main(String[] args)
{
int[] a = {1, 2};
swap(a);
System.out.println("a[0] = " + a[0] + " a[1] = " + a[1]);
}
public static void swap(int[] a)
{
int temp = a[0];
a[0] = a[1];
a[1] = temp;
}
}
a[0] = 2 a[1] = 1
c. (4 pts) Given the following program, show the values of the array in the following figure:
public class Test {
public static void main(String[] args) {
int[] values = new int[5];
for (int i = 1; i < 5; i++) {
values[i] = i;
}
values[0] = values[1] + values[4];
}
}
[pic]
d. 300
Part IV:
a.
matrix[0][1] + matrix[1][1] + matrix[2][1] + matrix[3][1]
int sum = 0;
for (int i = 0; i < 5; i++)
sum = sum + matrix[i][1];
b.
double[] list = new double[0];
System.out.println(list.length);
System.out.println(average(list));
/** if x is null, return 0. */
public static double average(double[] x) {
if (x == null) return 0;
double total = 0;
for (int i = 0; i < x.length; i++)
total += x[i];
return total / x.length;
}
c.
public class Test {
// Main method
public static void main(String[] args) {
int[] list = {1, 2, 4, 5, 10, 100, 2, -22};
System.out.println("The min is " + minIndex(list));
}
public static int minIndex(int[] list) {
int min = list[0];
int minIndex = 0;
for (int i = 1; i < list.length; i++)
if (min > list[i]) {
min = list[i];
minIndex = i;
}
return minIndex;
}
}
d.
public class Test {
public static int[] removeDuplicate(int[] x) {
int[] temp = new int[x.length];
int tempSize = 0;
for (int i = 0; i < x.length; i++) {
// Check if x[i] is already in temp
boolean duplicate = false;
for (int j = 0; j < tempSize; j++)
if (x[i] == temp[j])
duplicate = true;
if (!duplicate) {
// Add x[i] into temp
temp[tempSize] = x[i];
tempSize++;
}
}
int[] result = new int[tempSize];
System.arraycopy(temp, 0, result, 0, tempSize);
return result;
}
public static void main(String[] args) {
int[] x = {1, 3, 1, 2, 3, 5};
int[] result = removeDuplicate(x);
for (int i = 0; i < result.length; i++)
System.out.print(result[i] + " ");
}
}
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