INTEGRAL CALCULUS (MATH 106) - KSU
Outline Integration By Parts Integrals Involving Trigonometric Functions Trigonometric Substitutions Integration of Rational Function
INTEGRAL CALCULUS (MATH 106)
Dr. Borhen Halouani
king saud university
February 5, 2020
Dr. Borhen Halouani
INTEGRAL CALCULUS (MATH 106)
Outline Integration By Parts Integrals Involving Trigonometric Functions Trigonometric Substitutions Integration of Rational Function
1 Integration By Parts
2 Integrals Involving Trigonometric Functions
3 Trigonometric Substitutions
4 Integration of Rational Function
Dr. Borhen Halouani
INTEGRAL CALCULUS (MATH 106)
Outline Integration By Parts Integrals Involving Trigonometric Functions Trigonometric Substitutions Integration of Rational Function
Integration By Parts
It is used to solve integration of a product of two functions using the formula:
u dv = uv - v du
1 xex dx
u = x dv = ex dx
du = dx v = ex
xex dx = xex - ex dx = xex - ex + c
2 x sin x dx
0
u = x dv = sin x dx
du = dx v = - cos x
x sin x dx = [-x cos x ]0 + cos xdx = [-x cos x ]0 + [sin x ]0
0
0
[(- cos ) - (-(0) cos 0)] + [sin - sin 0] =
Dr. Borhen Halouani
INTEGRAL CALCULUS (MATH 106)
Outline Integration By Parts Integrals Involving Trigonometric Functions Trigonometric Substitutions Integration of Rational Function
Notes: 1 xex dx = (x - 1)ex + c x 2ex dx = (x 2 - 2x + 2)ex + c x 3ex dx = (x 3 - 3x 2 + 6x - 6)ex + c
2 x cos x dx = x sin x + cos x + c x 2 cos x dx = (x 2 - 2) sin x + 2x cos x + c x 3 cos x dx = (x 3 - 6x ) sin x + (3x 2 - 6) cos x + c x 4 cos x dx = (x 4 - 12x 2 + 24) sin x + (4x 3 - 24x ) cos x + c
3 x sin x dx = -x cos x + sin x + c x 2 sin x dx = (-x 2 + 2) cos x + 2x sin x + c x 3 sin x dx = (-x 3 + 6x ) cos x + (3x 2 - 6) sin x + c x 4 sin x dx = (-x 4 + 12x 2 - 24) cos x + (4x 3 - 24x ) sin x + c
Dr. Borhen Halouani
INTEGRAL CALCULUS (MATH 106)
Outline Integration By Parts Integrals Involving Trigonometric Functions Trigonometric Substitutions Integration of Rational Function
Integrals Involving Trigonometric Functions
First :Integrals of the forms
sin ax cos bx dx , sin ax sin bx dx , cos ax cos bx dx
Wher a, b Z
1 The integral sin ax cos bx dx can be solved using the formula
sin ax
cos bx
=
1 2
[sin(ax
+
bx )
+
sin(ax
-
bx )]
2 The integral sin ax sin bx dx can be solved using the formula
sin ax
sin bx
=
1 2
[cos(ax
-
bx )
-
cos(ax
+
bx )]
3 The integral cos ax cos bx dx can be solved using the
formula
cos ax
cos bx
=
1 2
[cos(ax
+
bx )
+
cos(ax
-
bx )]
Dr. Borhen Halouani
INTEGRAL CALCULUS (MATH 106)
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