MAS111 Strand 1: Solutions to Problems

1 cos2x 2: Then Z ˇ=3 0 cos2 2xdx= Z ˇ=3 0 1 + cos4x 2 dx= x 2 + sin4x 8 3 = ... 3x 6x 3x2 4x 4 = lim x!2 6x 6 6x 4 = 6 8 = 3 4: (b) We check that both numerator and denominator are 0 at x= 0. As long as this continues to be the case, we keep di erentiating top and ................
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