IIT JEE Syllabus - KEEEL

5 g of NaCl is dissolved in 1000 g of water. If the density of the resulting solution is 0.997 g per cc, calculate molality, molarity, normality and mole fraction of the solute. Solution: Mole of NaCl = = 0.0854 (Mol. wt. of NaCl = 58.5) Molality = = = 0.0854 m Volume … ................
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