Math 141: PRACTICE TEST # 1: Chapter 1 KEY
Solve for x or y in area equation ( x = 180 / y. Substitute into the perimeter equation ( 2(180/y) + 2y = 54. Multiply everything by the LCD = y ( 360 + 2y2 = 54y. Quadratic equation = 0, reduce the equation by dividing by 2, and use quadratic formula ( 2y2 – 54y + 360 = 0 ( y2 – 27y + 180 = 0. y = 12 or 15. ................
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