CP Worksheet - Charges and Coulomb’s Law



CP Worksheet 140 –Electrostatics Review

CP031312A

1. An ion contains 83 protons and 96 electrons. What is the charge on this ion?

Formula:

Answer:

2. True or False: Making the distance larger between the plates of a capacitor will increase the capacitance of the capacitor.

3. The electrostatic force between two ions is – 5.2 x 10-4 n. This means that the charges on the ions……

a. are both + or both –

b. have the same amount of charge

c. have one charge is + and the other –

d. have the same charge

4. What is the electrostatic force between two charges that have a charge of 1.296 x 10-17 C and 1.472 x 10-17 C. The charges are located 6.2 x 10-4 m apart.

Formula:

Answer:

5. An electric field is generated around the charge Q in the diagram below. At point A, what is the direction of the electric field?

a. up b. down c. left d. right

6. If an electron were placed at point B, What would be the direction of the electrostatic force on the electron.

a. up b. down c. left d. right

7. What is the strength of the electric field 9 m away from an ion with a charge of 9.6 x 10-16 C ?

Formula:

Answer:

8. An ion with a charge of 1.36 x 10-13 C is placed into an electric field of

8.2 x 1012 n/C. What is the electrostatic force on the ion?

Formula:

Answer:

9. What is the electric potential .4 m away from an ion with a charge of

9.6 x 10-16 C.

Formula:

Answer:

10. A parallel plate capacitor has a surface area of 3 x 10-2 m2. The plates are separated by a distance of 8 x 10-6 m. In between the plates is an insulating material with a dielectric constant of 5.6. What is the capacitance of the capacitor?

Formula:

Answer:

11. A parallel plate capacitor has a capacitance of 4.2 x 10-4 F. It is connected to a 12 volt battery and then fully charged up. What is the charge on the plates?

Formula:

Answer:

12. The electric field strength a certain distance from an ion is 8 n/C. If the distance from the charge is increased to be twice as great, what is the new strength of the electric field?

a. 16 n/C

b. 8 n/C

c. 4 n/C

d. 2 n/C

13. A parallel plate capacitor is connected to a 9 volt battery and fully charged. What is the strength of the electric field between the plates of the capacitor when the plates are 9.3 x 10-5 m apart?

Formula:

Answer:

14. The electric field caused by an ion is (– 5.2 x 10-7 n/C). This electric field was caused by…

a. a proton.

b. a positivity charged ion.

c. a negatively charged ion.

d. cannot be determined

Answers:

1. -2.08 x 10-18 C

2. False

3. C

4. 4.47 x 10-18 n

5. D

6. A

7. 1.067 x 10-7 n/C

8. 1.12 n

9. 2.16 x 10-5 V

10. 1.86 x 10-7 F

11. 5.04 x 10-3 C

12. D

13. 9.68 x 104 n/C

14. C

Formula Sheet- Electrostatics (Sheet 10)

CP030712D

FE = k q1 q2 e= + 1.6 x 10-19 C Q = n e

R2

k = 9 x 109 nm2 / C2 (constant)

Units

FE = Electrostatic Force n newtons

Q = Charge on an ion C Coulombs

R = Distance between ions (charges) m meters

n = Number of excess protons or electrons (none)

e = Charge of a single proton or electron C Coulombs

E = k Q

R2

E = Strength of the electric field n/C newtons/coulomb

R = Distance from the ion

FE = E Q

V = k Q

R

V = Voltage (Electric Potential) V volts

R = Distance from the ion m meters

Capacitors

C = Q

V

C = Capacitance of the capacitor F Farads

Q = Charge on the plates C Coulombs

V = Voltage on the plates V volts

C = κ εο A

D

κ ’ The dielectric constant of the insulating material No Units

εο ’ 8.85 x 10−12

A = The area of one plate m2 square meters

d = distance between the plates m meters

V = E d

V = Voltage on the plates V volts

E = Strength of the electric field n/C newtons/coulomb

Between the two plates

d = distance between the plates

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