Analiza I: 3. kolokvij - plonkec
: Če sta f in g zvezni funkciji na [a,b], odvedljivi na (a,b) in je g'(x) ≠ 0 za vse x med a in b, tedaj obstaja ξ med a in b, da je . L'Hopitalov. izrek: Če sta f in g odvedljivi na (a,b) in je g(x) ≠ 0 in g'(x) ≠ 0 za vse x med a in b in je in in obstaja tedaj obstaja tudi in je . INTEGRAL: lihe = soda. DOLOČENI INTEGRALI ................
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