Algebra I Chapter 4 Section 1, 3, and 4 Quiz Review Guide



Algebra I Chapter 4 Section 1, 3, and 4 Quiz Review Guide Solutions

Homework problems and class examples are a good resource for studying. The following is a list of the major concepts that are being covered on the quiz and what the students should expect to do on the quiz for each concept.

Coordinate Plane:

• Identify the coordinates of a point

• Graph a point on the coordinate plane

• Identify the quadrant of a point

Midpoint Formula: [pic]

• Find the midpoint of two points

Relations

• Represent a relation as a …

o Set of ordered pairs

o Table

o Graph

o Mapping

• Find the Inverse of a relation

• Identify the Domain and Range

Find the solution set of an equation given…

• Replacement set

• Domain

• Solve for the dependent variable

Practice Problems

1) What quadrant are each of the point located in?

o (-5, 5): Quadrant II

o (13, 9): Quadrant I

o (3, 0): No Quadrant

o (0, -4) : No Quadrant

o (-5, 7): Quadrant II

o (3, -2): Quadrant IV

2) What is the midpoint of…

o (-5, 5) and (13, 9): Midpoint = (4, 7)

o (3, -4) and (-7, 6): Midpoint = (-2, 1)

3) Starting at the point (2, -3). If you go up 3, left 5, down 7 and right 2, then what point do you end up at?

Start (2, -3); Up 3 = (2, 0); Left 5 = (-3, 0); Down 7 (-3, -7); Right 2 (-1, -7)

Solution: (-1, -7)

4) For the given relation (set of ordered pairs): {(0,3), (-2,4), (1, 5), (4, -3), (-1, -3)}

o Write the relation as TABLE.

|X |Y |

|0 |3 |

|-2 |4 |

|1 |5 |

|4 |-3 |

|-1 |-3 |

o Write the relation as a MAPPING.

o What is the DOMAIN and RANGE of the relation?

Domain = {0, -2, 1, 4, -1} Range = {3, 4, 5, -3}

o What is the INVERSE of the relation?

Inverse = {(3,0), (4, -2), (5, 1), (-3, 4), (-3, -1)}

5) Find the SOLUTION SET given the replacement set {(0, -2), (-1, 4), (3, 2), (1, 1), (2, 4)} and equation y = 3x – 2.

|X |Y |Equation y = 3x -2 |Solution? |

|0 |-2 |-2 = 3(0) – 2 |Yes |

|-1 |4 |4 = 3(-1) – 2 |No |

|3 |2 |2 = 3(3) – 2 |No |

|1 |1 |1 = 3(1) – 2 |Yes |

|2 |4 |4 = 3(2) – 2 |Yes |

o Write the SOLUTION SET from as a TABLE.

|X |Y |

|0 |-2 |

|1 |1 |

|2 |4 |

o Write the SOLUTION SET from as a MAPPING.

[pic]

o Write the INVERSE of the solution set as ordered pairs.

Inverse of Solution Set = {(-2, 0), (1, 1), (4, 2)}

6) Solve the equation 4x + 2y = 8 for the given domain = {-3, -1, 0, 2, 4}.

|X |4x + 2y = 8 or y = 4 – 2x |Y |

|-3 |4 – 2(-3) |10 |

|-1 |4 – 2(-1) |6 |

|0 |4 – 2(0) |-2 |

|2 |4 – 2(2) |2 |

|4 |4 – 2(4) |0 |

o Write the SOLUTION SET from as a set as ordered pairs.

Solution Set: (-3, 10), (-1, 6), (0, 4), (2, 0), (4, -4)

o Write the INVERSE of the solution set as TABLE.

|X |Y |

|10 |-3 |

|6 |-1 |

|4 |0 |

|0 |2 |

|-4 |4 |

o Write the INVERSE of the solution set as MAPPING.

[pic]

-----------------------

3

4

5

-3

0

-2

1

4

-1

Y

X

-2

1

4

0

1

2

Y

X

-3

1

0

2

4

10

6

4

0

-4

Y

X

................
................

In order to avoid copyright disputes, this page is only a partial summary.

Google Online Preview   Download