Section 5.2 Verifying Trigonometric Identities
[Pages:6]251 PART I: Solutions to Odd-Numbered Exercises and Practice Tests
127. sinA =-a==> a = c. sin A = 20 sin 28? ~ 9.39
c
B = 90? -A? = 62?
cosA=-b==~ b=c.cosA~ 17.66
c
129. a = ~/c2 - b2 = -~/12.542 - 6.22 ~ 10.90 sin B .bc..1. 2=6.=.52~4 B ~ 29.63? A = 90? - 29.63? = 60.37?
Section 5.2 Verifying Trigonometric Identities
[] You should know the difference between an expression, a conditional equation, and an identity. [] You should be able to solve trigonometric identities, using the following techniques.
(a) Work with one side at a time. Do not "cross" the equal sign. (b) Use algebraic techniques such as combining fractions, factoring expressions, rationalizing denominators,
and squaring binomials. (c) Use the fundamental identities. (d) Convert all the terms into sines and cosines.
Solutions to Odd-Numbered Exercises
1. sin t csc t = sin
= 1
csc2 x 1 sin x cot X sinE x cos x
CSCX " secx
1 sin x ? cos x
5. COSEft- sinEft= (1 -sinEft)- sin2fl = 1 -- 2 sinEfl
7. tanEo+6=(secE0- 1)+6
= sec2 19 + 5
sin x 9. cos x + sin x tan x = cos x + sin x ? ~
cos x
cos2 x + sin2 x
COS X
1
COS X
= sec X
11. x
Yl
?Y2
0.2 4.835 4.835
0.4 0.6 0.8 1.0 1.2 1.4 2.1785 1.2064 0.6767 0.3469 0.1409 0.0293 2.1785 1.2064 0.6767 0.3469 0.1409 0.0293
1
cos x
sec x tan x = COS Xs*in~x
COS2 x
sin x 1 - sin2 x
sin x
1 sin x
sin x
= csc x - sin x
252 PART 1: Solutions to Odd-Numbered Exercises and Practice Tests
13. x
Yl Y2
0.2 4.835 4.835
0.4 0.6 0.8 1.0 1.2 1.4 2.1785 1.2064 0.6767 0.3469 0.1409 0.0293 2.1785 1.2064 0.6767 0.3469 0.1409 0.0293
o o
cscx
-
1 sinx s=in x~-
sin x
1 - sin2 x
sin x
cos2 x
sin x
=
COS
X
?
COS x
sin x
-" COSX " cotx
15. i X
Yl Y2
0.2 0.4 5,0335 2.5679 5.0335 2.5679
0.6 1.7710 1.7710
0.8 1.3940 1.3940
1.0 1.1884 1.1884
1.2 1.0729 1.0729
1.4 1.0148 1.0148
sin
x
+
cos
x
cot
x
=
sin
x
+
cos
'xCs.OmS
X
x
_,_ sin2 x + cos2 x sin x
1 sin x
= csc x
1.5
17. x 0.2 0.4 0.6 0.8 Yl 5.1359 2.7880 2.1458 Y2 5.1359 2.7880 2.i458
1.0 1.2 1.4 2.1995 2.9609 5.9704 2.1995 2.9609 5.9704
~1 +~1 =c?tx+tanx tanx cotx tanx.cotx
= cot x + tan x
oo
19. The error is in line 1: cot(- x) #'cot x.
21. Missing step: (sec2x - 1)2 = (tan2 X)2 -" tarl4 x
23. sin~/2 x cos x - sin~/2 x cos x = sin1/2 x cos x(1 - sin2 x) = sint/2 x cos x ? cos2 x = coss x.,/~ffx
-- X SeCX = COtX" secx
1
27. scees(c-(x-.x__)._..~) = c1os(-x) =csoins((--xx))
- ~sin=x- tan x
COS X
253 PART 1: Solutions to Odd-Numbered Exercises and Practice Tests
29.
cos(-0)
1 + sin(-0)
cos 0 1 + sin 0 1-sin0 1 +sin0
cos ~(1 + sin 0) 1 - sin2 0_
cos ~(1 + sin O) cos2 ~
1 + sin O
~os 0
1 sin 0
cos 0 cos O
= sec 0 + tan 0
31.
sin x cos y + cos x sin y cos x cos y - sin x sin y
sin x cos cos x Cos y
y +
cos x cos x
sin cos
y y
cos x cos y sin x sin y cos x cos y cos x cos y
tan x + tan y 1 - tan x tan y
1
1 tan y + cot x
33.
tan x + cot y -tan x cot y
cot x tan y cot x ? tan y
1 1
1
= tan y + cot x
cot
o
x tan
y
cot
x
?
tan
y
35. ~/~+sinO_ ~/~+sinO. l+sinO -sinO -sinO 1 +sinO + sin 0)2 =~/(i -- sin2 0
Note: Check your answer with a graphing utility. What happens if you leave off the absolute value?
cos2 O 1 + sin 0
37. cos2x+cos -x =cos2x+sin2x= 1
?
-x =secx.cosx= 1
41. 2 sec2 x -- 2 secx x sin2 x - sin2 x -- COS2 x = 2 sec2 x(1 - sin2x) - (sin2 x + cos2 x) = 2 sec2 x(cos2 x) -- 1 1 =2"~"ccoos2s2xx- 1 =2-1 =1
43. 2 + cos2x - 3 cos'ix = (1 - cos2 x)(2 + 3 cos2 x) = sin2 x(2 + 3 cos2 x)
254 PART I: Solutions to Odd-Numbered Exercises and Practice Tests
45. csc4 x - 2 csc2 x + 1 = (csc2 x - 1)2 = (cot2 x)2 = cot4 x
47. see4 0 - tan4 0 = (see2 0 + tall20)(sec2 0 -- tan2 O) -- (1 + tanz 0 + tan2 0)(1) = 1 + 2tan20
49.
sin/3 1 -cos/3
1 + cos/3 1 +cos/3
--
sin f!(1 + cos f!) 1 - cos2/3
sin/3(1 + cos/3) 1 + cos/3
sin2/3
--
sin/3
51. ttaann3aa--11 (-tan a - 1)(tatna2naa+- t1an a + ~1) =tan2a+tana+ 1
53. It appears that Yl = 1. Analytically, 1 +1 tanx-+ 1 +cotx+ 1
cotx + 1 tan x + 1 (cot x + 1)(tanx + 1)
.--.
tanx + cotx + 2
cotxtanx + cotx + tanx + 1
tan x -t- cot x ? 2 tanx+cotx+2
=1.
55. It appears that Yl -" Sin X. Analytically,
1
COS2 X --
1 -- COS2 X
--
sin2x - sinx.
sin x sin x sin x sinx
2
57. Inlcot 01 - _ Icos 0
- tnlsin 01 - lnlcos 0l - Inlsin 01
-2
59. -ln(1 + cos 0) = In(1 + cos 0)-1
= lnl +cosO 1 -cos
=ln
1 1
-
cos 0 cos2 0
=In
1
- cos sin2 0
0
= In(1 - cos 0) - In sin2 0
= In(1 - cos o) - 2 Inlsin ol
61. sin2 25? + sin2 65? = sin2 25? + cos2 25? = 1
255 PART 1: Solutions to Odd-Numbered Exercises and Practice Tests
63. cos2 20? + cos2 52? + cos~ 38? + cos2 70? = c?s2 20? + c?s2 522 + sin2(90? - 38?) + sin2(90? - 70?) = cos2 20? + cos~ 522 + sin252? + sinz 20? = (cos2 20? + sin2 20?) + (cos~ 52? + sin~ 52?) =1+1 =2
65. tanS x = tanax " tan2 x = tan3 x(sec2 x - 1) = tan3 x sec2 x -- tan3 x
67. (sinz x - sin~ x)cos x = sin~ x(1 - sinz x)cos x
-- sin2X ? COS2 X ? COS X = COS3 X sin2 x
69. /zW cos 0 = W sin 0
W sin 0 sin 0 /z W cos 0 cos 0
tan 0, W 4:0
71. cos x - csc x. cot x = cos x
1 cos x
sin x sin x
cos
sina
- cos x(1 - csc2 x)
= cos x(-cot~ x)
73. True. f(x) = cos x and g(x) = sec x are even
75. False. For example, sin(l,z) 4: sinz (1)
79? ~/sin~ x + cos2x 4: sin x + cos x The left side is 1 for any x, but the right side is not necessarily 1. For example, the equation is not tree for x = 7r/4.
+ 1)~! = sin[51-(12n~r + ~r)l $1. sinI(12n 6
= sin(2n,rr + -~) = sin"6t2-r 1 Thus, sin[(126n ? 1?)qr=]~1for all integers
83. (x- i)(x + i)(x- 4i)(x + 40 = (x~ + 1)(x2 + 16) =x*+ 17xz+ 16
256 PART 1: Solutions to Odd-Numbered Exercises and Practice Tests
87. f(x) = -2x-3
y
89, f(x) = 5-x - 2
y
2 4 6
91. s = rO
0
-
s r
12-16
~ 2.3636 radians
93. Quadrant III
95. Quadrant III
Section 5.3 Solving Trigonometric Equations
[] You should be able to identify and solve trigonometric equations. [] A trigonometric equation is a conditional equation. It is true for a specific set of values. [] To solve trigonometric equations, use algebraic techniques such as collecting like terms, taking square roots,
factoring, squaring, converting to quadratic form, using formulas, and using inverse functions. Study the examples in this section. I Use your graphing utility to calculate solutions and verify results.
Solutions to Odd-Numbered Exercises 1. 2cosx- 1 =0
(a) 2cos~- 1 =2 - 1 =0 (b) 2cos'~'-- 1 = 2 - 1 =0
3. 3tan22x- 1 =0
(a) 3 tan\-~-/j - 1 = 3~an2-~- 1
=3
-1
=0
(b) [3(ltOa'nnk']]212~_]~J -1 =3tan~ - 1
=0
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