Logarithm and Exponents 2: Solving equations

log5 x = log2 log2 log5 1.25 4) Rewrite using base 5: a) b) 0.4x 2(25) -o.2x (4) 2 0.4x o.8x 2(5) Find 5 log5X = log4 log4 log5 _8 -o.2x -.17X (5) (approx) 5) Find the inverses: SOLUTIONS h(x) 3 3 3 log(2 + x) log(2 + x) log(2 + Y) Logarithm 2 Practice Test 6) f(x) x 16 16 + 16 = 16 switch x and y ................
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