(1.1) E log2 p + D log p log q = 2x log x + O(x). V(X) - Z ...
(1.1) E log2 p + D log p log q = 2x log x + O(x). ply pq~x The proof of (1.1) may be reduced to the evaluation of the sum V(X) - Z (d) log2 x/d. d-1 d More precisely (1.1) is equivalent to the assertion that (1.2) V(x) = 2 log x + 0(1). In this note we propose to give a simple proof of (1.2) and its equivalence with ................
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